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Cell2table issues when a numerical column is read as strings
I would also have many columns, some of which could be made up of: (a) all doubles (b) a mix of empty strings (e.g., ' ', ' ...
Cell2table issues when a numerical column is read as strings
I would also have many columns, some of which could be made up of: (a) all doubles (b) a mix of empty strings (e.g., ' ', ' ...
約9時間 前 | 0
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Pagewise multiplication along a dimension without using a for loop?
No, but looking at your code, I would guess that the speed is being encumbered much more by the operation length(X(1,1,1,:)) tha...
Pagewise multiplication along a dimension without using a for loop?
No, but looking at your code, I would guess that the speed is being encumbered much more by the operation length(X(1,1,1,:)) tha...
約14時間 前 | 1
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Add a class folder to path
Nothing is wrong. @-directories should not and do not need to be on the path as long as their parent directory is. You can auto...
Add a class folder to path
Nothing is wrong. @-directories should not and do not need to be on the path as long as their parent directory is. You can auto...
1日 前 | 0
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How to read all rows of an Excel with missing rows included?
ActiveX can be used to determine the last row/column of the worksheet: Then, you can force readcell to read in a larger range wi...
How to read all rows of an Excel with missing rows included?
ActiveX can be used to determine the last row/column of the worksheet: Then, you can force readcell to read in a larger range wi...
2日 前 | 0
質問
Make gca() responsive to appDesigner axes clicks
I have an appdesigner app such as below with a uipanel containing regular images (not uiimages). I also have many, many standal...
3日 前 | 1 件の回答 | 0
1
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polyshape not closing a circle
An added complication is that the resulting union may have multiple regions, so I cannot just duplicate the first vertex to the ...
polyshape not closing a circle
An added complication is that the resulting union may have multiple regions, so I cannot just duplicate the first vertex to the ...
3日 前 | 0
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How can I create multiple function handles in a for loop?
The best would be to just have a matrix-valued function, fun=@(x) x.^2-mymat(:).*x+mymat(:) but you could make a cell array of...
How can I create multiple function handles in a for loop?
The best would be to just have a matrix-valued function, fun=@(x) x.^2-mymat(:).*x+mymat(:) but you could make a cell array of...
4日 前 | 0
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Filtering Blobs on a Binary Image
If you can form an under-estimate of the extent of the blobs, let's call them sub-blobs, then you can fit a Gaussian lobe to the...
Filtering Blobs on a Binary Image
If you can form an under-estimate of the extent of the blobs, let's call them sub-blobs, then you can fit a Gaussian lobe to the...
4日 前 | 0
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Why does the Code Analyzer flag this as an error?
Mathworks Support has classified it as a bug.
Why does the Code Analyzer flag this as an error?
Mathworks Support has classified it as a bug.
5日 前 | 1
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How do you change the output dimension of a NN layer?
Should I flatten the inputs and then concatenate them similar to this example? Probably. See if the attached network does what...
How do you change the output dimension of a NN layer?
Should I flatten the inputs and then concatenate them similar to this example? Probably. See if the attached network does what...
6日 前 | 0
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Display a small matrix as a gray scale image
T2 =[ 0.4706 0.9804 0.8392 0.3216 0.9804 0.8392 0.3216 0.4706 0.8392 0.3216 0.4706 0.9...
Display a small matrix as a gray scale image
T2 =[ 0.4706 0.9804 0.8392 0.3216 0.9804 0.8392 0.3216 0.4706 0.8392 0.3216 0.4706 0.9...
6日 前 | 0
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How to freeze specific neuron weights in a feedforward network during training process?
I don't think you can do it without the Deep Learning Toolbox. If you have the Deep Learning Toolbox, you can define a custom la...
How to freeze specific neuron weights in a feedforward network during training process?
I don't think you can do it without the Deep Learning Toolbox. If you have the Deep Learning Toolbox, you can define a custom la...
6日 前 | 0
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Please help with this multiplication problem
You can multiply directly. Example: [m,n,r]=deal(3,4,2); A=rand(m,1,r); B=rand(1,n,r); C=A.*B; whos A B C
Please help with this multiplication problem
You can multiply directly. Example: [m,n,r]=deal(3,4,2); A=rand(m,1,r); B=rand(1,n,r); C=A.*B; whos A B C
6日 前 | 0
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sub2ind() errors out with NaN inputs - handled differently since R2024a
You can get the old behavior back if you need it, Sub2Ind([ 3 5 7], [ 3 3], [2 2], [1 nan]) function out=Sub2Ind(sz,vararg...
sub2ind() errors out with NaN inputs - handled differently since R2024a
You can get the old behavior back if you need it, Sub2Ind([ 3 5 7], [ 3 3], [2 2], [1 nan]) function out=Sub2Ind(sz,vararg...
6日 前 | 0
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Non-linear constraints format for GA using solve function
I would formulate it as, N=numel(Pos_Input_mtx); problem.Constraints.c1=abs(Pos_Input_mtx(:)-Pos_Input_mtx(:)') >= (1-eye(N)...
Non-linear constraints format for GA using solve function
I would formulate it as, N=numel(Pos_Input_mtx); problem.Constraints.c1=abs(Pos_Input_mtx(:)-Pos_Input_mtx(:)') >= (1-eye(N)...
7日 前 | 0
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Summing function handles of multiple variables across one of the variables
Nesting function handles n-fold is going to be very inefficient, and is usually not a good idea. Usually, it is best to vectoriz...
Summing function handles of multiple variables across one of the variables
Nesting function handles n-fold is going to be very inefficient, and is usually not a good idea. Usually, it is best to vectoriz...
7日 前 | 0
回答済み
Error using trainNetwork Invalid training data. For classification tasks, responses must be a vector of categorical responses. For regression tasks, responses must be a vector
Instead of using Matlab's dicePixelClassificationLayer, you can try the following custom output layer: classdef GeneralizedDice...
Error using trainNetwork Invalid training data. For classification tasks, responses must be a vector of categorical responses. For regression tasks, responses must be a vector
Instead of using Matlab's dicePixelClassificationLayer, you can try the following custom output layer: classdef GeneralizedDice...
9日 前 | 0
回答済み
Ifft2 results do not match that of irfft2 in Pyhton
I'm not a Python user, but if rfft2 only gives you positive x-frequencies, I would imagine it also only gives you positive y-fre...
Ifft2 results do not match that of irfft2 in Pyhton
I'm not a Python user, but if rfft2 only gives you positive x-frequencies, I would imagine it also only gives you positive y-fre...
11日 前 | 0
質問
Three dots at the end of a line of code
Why does one of my lines of code have three dots enclosed in a box? What does it mean? Clicking on it does nothing.
11日 前 | 1 件の回答 | 0
1
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Looking for linear system Ax=0 precision improvements
s=max(abs(A),[],1); x = null(A./s)./(s')
Looking for linear system Ax=0 precision improvements
s=max(abs(A),[],1); x = null(A./s)./(s')
12日 前 | 0
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Finding x and y values of minimum z in 2-variable function.
The continuous minimum can't be at (5,2) as you claim. Direct evaluation shows that the value of z at (5.5,10) is lower. loopi...
Finding x and y values of minimum z in 2-variable function.
The continuous minimum can't be at (5,2) as you claim. Direct evaluation shows that the value of z at (5.5,10) is lower. loopi...
12日 前 | 0
回答済み
Using fft and ifft with less frequencies than input points
What I would want to do, is to insert an N, f.e. N=100, but get an array 10001x1. %Grid Nx = 100; L = 10; dx = L/(Nx-1); ...
Using fft and ifft with less frequencies than input points
What I would want to do, is to insert an N, f.e. N=100, but get an array 10001x1. %Grid Nx = 100; L = 10; dx = L/(Nx-1); ...
12日 前 | 0
質問
Why does the Code Analyzer flag this as an error?
Why does the Code Analyzer flag this code as an error? It runs fine: try error("It's bad") catch ME warning('Error...
12日 前 | 2 件の回答 | 0
2
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How to fastly calculate this real number matrix manipulation?
e=(1:A)'; I=reshape(e,1,1,[]) == repmat( e,1,B); Xp=permute(X,[3,2,1]); D=X./(X-Xp); D(I)=1; M = ipermute( prod(D,1) ,[...
How to fastly calculate this real number matrix manipulation?
e=(1:A)'; I=reshape(e,1,1,[]) == repmat( e,1,B); Xp=permute(X,[3,2,1]); D=X./(X-Xp); D(I)=1; M = ipermute( prod(D,1) ,[...
14日 前 | 0
回答済み
How to solve the error generated while defining custom FFT layer?
Your predict() method is written to expect that the input X will be a cell array. It's not clear why you expect this, but you sh...
How to solve the error generated while defining custom FFT layer?
Your predict() method is written to expect that the input X will be a cell array. It's not clear why you expect this, but you sh...
14日 前 | 0
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How do I edit a loop to be able to store the variables and outputs used in each loop in a way which can be graphed?
D = 0.3 k = 0.0002 Rvalues = 10^4:10^5:10^8; nR=numel(Rvalues); X=nan(1,nR); for i=1:nR R=Rvalues(i); ...
How do I edit a loop to be able to store the variables and outputs used in each loop in a way which can be graphed?
D = 0.3 k = 0.0002 Rvalues = 10^4:10^5:10^8; nR=numel(Rvalues); X=nan(1,nR); for i=1:nR R=Rvalues(i); ...
15日 前 | 0
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reshape 4-dimension array
Download this File Exchange package, https://www.mathworks.com/matlabcentral/fileexchange/115340-block-transposition-permutatio...
reshape 4-dimension array
Download this File Exchange package, https://www.mathworks.com/matlabcentral/fileexchange/115340-block-transposition-permutatio...
16日 前 | 0
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Speed up this bottleneck line of code
If you can construct c in transposed form, there are some savings to be had, n = 10000; m = 5000; k = 20; a = rand(n,m);...
Speed up this bottleneck line of code
If you can construct c in transposed form, there are some savings to be had, n = 10000; m = 5000; k = 20; a = rand(n,m);...
17日 前 | 0
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nonlinear spline fit with unknown upper bound of interpolation domain
The upper bound is way larger than the fitted parameters at x < 6, causing an extremly large curvature at x > 6 which makes the ...
nonlinear spline fit with unknown upper bound of interpolation domain
The upper bound is way larger than the fitted parameters at x < 6, causing an extremly large curvature at x > 6 which makes the ...
20日 前 | 0
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Differentiating in one direction using FFT2
fft2(u) is equivalent to fft( fft(u,[],1) ,[],2), if that helps at all. Truthfully, it doesn't appear that you need to use fft2...
Differentiating in one direction using FFT2
fft2(u) is equivalent to fft( fft(u,[],1) ,[],2), if that helps at all. Truthfully, it doesn't appear that you need to use fft2...
21日 前 | 0
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