Why does the second matrix start with zeros?

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Spencer Checkoway
Spencer Checkoway 2020 年 7 月 31 日
コメント済み: Adam Danz 2020 年 7 月 31 日
for i=-10:10
if i<0
a(i+11)=i;
if i>0
b(i+10)=i;
end
end
end
Out of curiosity, why, if I print b, would the matrix start with 10 zeros?
  1 件のコメント
Adam Danz
Adam Danz 2020 年 7 月 31 日
"Out of curiosity, why, if I print b, would the matrix start with 10 zeros?"
This code should never reach 'b' which would leave 'b' undefined. The i>0 condition is nested within the i<0 condition. So if i<0, than i will never be greater than 0.
Here is your code with correct formatting.
for i=-10:10
if i<0
a(i+11)=i;
if i>0
b(i+10)=i;
end
end
end
My guess is that one of your 'end' lines is misplaced.
Even if you fix it, you'd still have problems getting what you want for reasons described by madhan ravi.

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採用された回答

madhan ravi
madhan ravi 2020 年 7 月 31 日
編集済み: madhan ravi 2020 年 7 月 31 日
MATLAB assigns zero to the previous indices, for better understanding:
clear a
a(11) = 1; % now you will see elements from 1-10 are filled with zeros, if a doesn’t exist already in the workspace
Perhaps what you want is:
ii = -10 : 10;
a = ii(ii < 0)
b = ii(ii >= 0)

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