no output when coding

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Boss Man
Boss Man 2020 年 2 月 10 日
編集済み: Adam Danz 2020 年 5 月 14 日
a = xlsread('outdoorall.xlsx','H2:H52364');
b=xlsread('indoorall.xlsx','H2:H52364'); %2397
t=xlsread('outdoorall.xlsx','E2:E52364');% time in secs
for i=1:2363
dti=t(i+1)-t(i);
dt=(b(i+1)-b(i))/dti; % change in indoor temperature divided by time
c=dt/a(i)-b(i);
plot(c)
end
the idea is each time step is different so i want to divide the change in temp by each unique time step
  5 件のコメント
Adam Danz
Adam Danz 2020 年 2 月 11 日
編集済み: Adam Danz 2020 年 5 月 14 日
Copy of question
a = xlsread('outdoorall.xlsx','H2:H52364');
b=xlsread('indoorall.xlsx','H2:H52364'); %2397
t=xlsread('outdoorall.xlsx','E2:E52364');% time in secs
for i=1:2363
dti=t(i+1)-t(i);
dt=(b(i+1)-b(i))/dti; % change in indoor temperature divided by time
c=dt/a(i)-b(i);
plot(c)
end
the idea is each time step is different so i want to divide the change in temp by each unique time step
___________________________________________________________
My comment
Try
c = nan(1, 2363);
for i=1:2363
dti=t(i+1)-t(i);
dt=(b(i+1)-b(i))/dti; % change in indoor temperature divided by time
c(i)=dt/a(i)-b(i);
end
plot(c)
or
hold on
for i=1:2363
dti=t(i+1)-t(i);
dt=(b(i+1)-b(i))/dti; % change in indoor temperature divided by time
c=dt/a(i)-b(i);
plot(c, 'o')
end
Rena Berman
Rena Berman 2020 年 5 月 14 日
(Answers Dev) Restored edit

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採用された回答

Hank
Hank 2020 年 2 月 11 日
編集済み: Hank 2020 年 2 月 11 日
Do this without a for loop
% Load data
a = xlsread('outdoorall.xlsx','H2:H52364');
b=xlsread('indoorall.xlsx','H2:H52364'); %2397
t=xlsread('outdoorall.xlsx','E2:E52364');% time in secs
a = a(:); b = b(:); t = t(:); % make sure we're working with column vectors
dti = diff(t) % difference between each value of t, length is one less than 1;
% it looks like your formula is the difference in db/dt divided by the difference between a and b.
% Pad db/dt with 0 so the array length matches with a and b.
c = [0; diff(b)./dt] ./ (a-b) ;
plot(t,c)
is this what you're trying to do?
  4 件のコメント
Stephen23
Stephen23 2020 年 2 月 11 日
"I need it to be consecutive values so i dont think rand would be useful to me."
You did not provide a, b, or t, so Adam Danz quite reasonably just used some matrices of random values in order to actually run the code on something.
You should use your own arrays, of course, not the random values that are just used for testing.
Boss Man
Boss Man 2020 年 2 月 11 日
apologies, thought i attached the data

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