counting rows after fprintf

function  printPythagoras(n) 
  n = 15;
  for i = 3:n
    for j = 4:n 
      for k = 5:n
        if i^2 + j^2 == k^2 && i<j && n == fix(n)
          fprintf('%d^2 + %d^2 = %d^2\n',i,j,k)       
        end 
      end  
    end
end

---------------

after that , i need to write : 'there are 4 combinations' (the number of the rows)

how to do it?

[dpb]

Add a counter inside the if block, then the appropriate fprintf statement after the all looping is done...

Answer 1

[Adam Danz]

As dpb advised, you could use a counter.

n = 15;
counter = 0;
for i = 3:n
    for j = 4:n
        for k = 5:n
            if i^2 + j^2 == k^2 && i<j && n == fix(n)
                counter = counter+1; 
                fprintf('%d^2 + %d^2 = %d^2\n',i,j,k)       
            end
        end
    end
end
% Show count
fprintf('There are %d combinations.\n', counter)

Or you could store the outputs in a cell array and display them and the count at the end.

n = 15;
out = {};
for i = 3:n
    for j = 4:n
        for k = 5:n
            if i^2 + j^2 == k^2 && i<j && n == fix(n)
                out{end+1,1} = sprintf('%d^2 + %d^2 = %d^2',i,j,k);
            end
        end
    end
end
% Display
disp(strjoin(out,'\n'))
% Show count
fprintf('There are %d combinations.\n', numel(out))

[yonatan friedman]

thank you