for loop that changes specific letters to numbers

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Seaturtle
Seaturtle 2019 年 10 月 2 日
コメント済み: Adam Danz 2019 年 10 月 4 日
I want to replace the vowels AEIOU with the number 0 and all other letters with the number 1. For example the output should be ans = [0 1 1 1 0] if the user inputs apple. I know I must be misunderstanding how to get the loop to go through my whole string. This is what I have managed so far.
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if i == 'A'
disp(0)
elseif i == 'B'
disp(1)
elseif i == 'C'
disp(1)
end
end

採用された回答

Walter Roberson
Walter Roberson 2019 年 10 月 2 日
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if party(i) == 'A'
party(i) = 0;
elseif i == 'B'
party(i) = 1;
elseif i == 'C'
party(i) = 1;
end
end
disp( double(party) )
  7 件のコメント
Adam Danz
Adam Danz 2019 年 10 月 3 日
True. It would be neat to play around with one of the vowel classification algorithms that are not specific to any language such as this one (link below) that is based on character co-occurrences. It wouldn't necessarily solve the fuzzy set problem but it would be a semi-objective, language-independent classification.

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その他の回答 (2 件)

Adam Danz
Adam Danz 2019 年 10 月 2 日
編集済み: Adam Danz 2019 年 10 月 2 日
No loop needed.
str = 'apple';
isConsonant = ~ismember(lower(str),'aeiou') %lower() makes it not case sensitive
If you really wanted to do that in a loop,
n = numel(party);
isConsonant = true(1,n);
for i = 1:n
if ismember(party(i),'aeiou')
isConsonant(i) = false;
end
end
In both cases, isConsonant is a logical vector. If you want a double vector of 0/1 instead of false/true,
isConsonant = double(isConsonant);
  8 件のコメント
Adam Danz
Adam Danz 2019 年 10 月 3 日
Glad I could chip in! :)

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Jos (10584)
Jos (10584) 2019 年 10 月 3 日
Another option:
str = 'apple';
TF1 = any(lower(str) ~= 'aeiou'.')
  6 件のコメント
Adam Danz
Adam Danz 2019 年 10 月 4 日
+1
This implicit expansion solution is faster and neater than my ismember() solution.

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