How to get the absolute value of the a vector inside an array?

18 ビュー (過去 30 日間)
Ana Bianco
Ana Bianco 2019 年 9 月 10 日
編集済み: Stephen23 2019 年 9 月 11 日
Hi there, I am trying to extract the absolute value of the column vectors inside an array, but it keep giving me the message: Array indices must be positive integers or logical values., for the following code:
absvec = [];
for a = 1:270
for b =1:10
abs(H{a,b}) = absvec (a,b),
end
end
can anyone help me?
  2 件のコメント
Adam Danz
Adam Danz 2019 年 9 月 10 日
編集済み: Adam Danz 2019 年 9 月 10 日
Either that's not the error message you're getting or you shared the wrong code with us.
The error message returned by your code is "Index in position 1 exceeds array bounds." (r2019a) Of course this is happeneng because absvec is empty and you're trying to index it.
do you mean
absvec (a,b) = abs(H{a,b}) % ???
Ana Bianco
Ana Bianco 2019 年 9 月 11 日
I may have confused which came first, thank you!

サインインしてコメントする。

採用された回答

Sebastian Körner
Sebastian Körner 2019 年 9 月 10 日
relly not sure if this is what your question is about but maybe it helps.
since you provided no data to your problem i created some example data myself.
H ={[5,-6],[5,-6];[7,-8],[7,-8];[5,-6],[5,-6];[7,-8],[7,-8]};
v=1;
for i=1:4
for k=1:2
h(:,v)=abs(H{i,k});
v=v+1;
end
end
input: cell array with cevtors in each cell
output: a vector with the absolute values of each vector of the cell array
  2 件のコメント
Ana Bianco
Ana Bianco 2019 年 9 月 11 日
That is just perfect! Exactly what I wanted.
Thanks Sebastian!
Stephen23
Stephen23 2019 年 9 月 11 日
編集済み: Stephen23 2019 年 9 月 11 日
Simpler and more efficient with a comma-separated list:
>> out = abs(cat(1,H{:}))
out =
5 6
7 8
5 6
7 8
5 6
7 8
5 6
7 8
Timing (1e5 iterations):
Elapsed time is 13.833 seconds. % nested loops
Elapsed time is 2.239 seconds. % comma-separated list

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by