could anyone help me to solve the issue
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I am having a matrix with values of
[1 0 0 1;
0 1 1 0]
I want to display the above matrix in thefollowing manner
[1.0000 0.0000 0.0000 1.0000;
0.0000 1.0000 1.0000 0.0000]
could anyone please help me on it.
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採用された回答
madhan ravi
2019 年 8 月 8 日
編集済み: madhan ravi
2019 年 8 月 8 日
ix = [repmat('%.4f ',1,size(a,2)-1),'%.4f\n']; % where a is your matrix
fprintf(ix,a.')
% or perhaps you need
result = sprintfc('%.4f',a) % undocumented
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その他の回答 (1 件)
KALYAN ACHARJYA
2019 年 8 月 6 日
編集済み: KALYAN ACHARJYA
2019 年 8 月 6 日
result=compose('%1.4f',A)
compose here
2 件のコメント
Adam Danz
2019 年 8 月 8 日
編集済み: Adam Danz
2019 年 8 月 8 日
There are two issues here and it's important to understand why a solution is not working.
First, the matrix you provided in your question which Kalyan called "A" is numeric. So the input to compose() is numeric, not char. First you need to confirm what "A" is (see below) or just copy-paste A into a comment so we can see it.
class(A)
Second, compose() does allow for character inputs so the error you're getting could indicate that you're using a matlab release prior to 2016b which was when compose() was released.
ver()
If you are using a release prior to r2016b and your input is indeed a numeric matrix like the one in your question, you could use this below or the other answer provided here. However, KALYAN 's approach is best if you're working with r2016b.
A = [1 0 0 1;
0 1 1 0];
c = strsplit(sprintf('%.4f\n', A));
result = reshape(c(1:end-1),size(A))
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