How can I create a Figure Title with a variable in it?

186 ビュー (過去 30 日間)
onamaewa
onamaewa 2019 年 5 月 28 日
編集済み: Stephen23 2019 年 5 月 29 日
I have a figure:
DEPTH = 10; % Depth changes based on user input
figure('Numbers at a depth of %d meters)')
How can I make my figure title update depending on my input for depth?

回答 (1 件)

Adam Danz
Adam Danz 2019 年 5 月 28 日
編集済み: Adam Danz 2019 年 5 月 29 日
DEPTH = 10; % Depth changes based on user input
title(sprintf('Numbers at a depth of %.0f meters', DEPTH))
% For the figure name (not title):
figure('Name', sprintf('Numbers at a depth of %.0f meters', DEPTH))
I prefer %.0f rather than %d to convert integers because 1) if DEPTH isn't an integer, %d will print out scientific notation and 2) if you ever want to add decimal places you can just change the 0.

カテゴリ

Help Center および File ExchangeTitle についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by