Finding the index of spesific element in a matrix?
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Lets say we have matrix:
a=[ 2, 3, 5
3, 4, 7
4, 4, 4] ;
I want to know index of a(4) which is the bold 3. This is just an example. I want to learn how to find index of a(n).
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madhan ravi
2019 年 5 月 23 日
編集済み: madhan ravi
2019 年 5 月 23 日
Assuming you want to index of the last match in the matrix:
Index=find(a==3,1,'last')
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madhan ravi
2019 年 5 月 23 日
編集済み: madhan ravi
2019 年 5 月 23 日
No problem, by the way the original question you asked is totally irrelevant to your latter comment. Please don’t do this in the future riddling the answers.
Look into ind2sub() function to convert the linear indices. To understand what this statement means , you need to read the link which I shared thoroughly and practice. And finally have a look at ind2sub().
その他の回答 (1 件)
KALYAN ACHARJYA
2019 年 5 月 23 日
編集済み: KALYAN ACHARJYA
2019 年 5 月 23 日
I want to know index of a(4) which is the bold 3
here ......................... this 4^ represent the index, I guessing you are looking for following one.
idx=find(a==3);
One dimentional case array case
>> a=[2,3,5,3,4,7,4,4,4];
>> idx=find(a==7)
idx =
6
>> idx=find(a==3)
idx =
2 4
But Matrices have 2 dimention so indices represents (x,y), where answer will be little different
>> a=magic(3)
a =
8 1 6
3 5 7
4 9 2
>> [r c]=find(a==3)
r =
2
c =
1
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