Hi there. I have a 4 column by 500 row matrix. How would I add a fifth column that calculates , where x is the corresponding value in the second column across the same row.
Thanks!

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madhan ravi
madhan ravi 2019 年 4 月 22 日

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D=zeros(500,5);
D=matrix;
D(:,5)=exp((-(matrix(:,2)-75)/2).^2)

3 件のコメント

Jenny Hall
Jenny Hall 2020 年 10 月 22 日
I am currently trying to do something similar, in order to carry out a calculation of every value in one column. This code I have written is as follows:
x(:,2) = (((6.64e-34)*(9.5e+9))/((9.274e-24)*(x(:,1)/10000)))
However this only seems to calculate a value for the final row in the column, whilst all of the values come out as 0. The column contains 1024 rows.
Any help would be much appreciated!
Stephen23
Stephen23 2020 年 10 月 22 日
編集済み: Stephen23 2020 年 10 月 22 日
x(:,2) = (((6.64e-34)*(9.5e+9))./((9.274e-24)*(x(:,1)/10000)))
% ^^ you might want array division here
Jenny Hall
Jenny Hall 2020 年 10 月 22 日
Thank you! This worked a treat.

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JULIEN BARBAUD
JULIEN BARBAUD 2019 年 4 月 22 日
編集済み: JULIEN BARBAUD 2019 年 4 月 22 日

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I think that if you call your input matrix A, and the final result B, then this:
f=@(x) exp( (-(x-75)/2).^2 )
B=[A f(A(:,2))];
should do the trick
EDIT: oops, madhan was quicker

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