why the coordinates start from 800. want it to start from 0 . and the origin point in the left down like usual.

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this the code i use
%load the image called test1
rgbImage = imread('test1.JPG');
% Get the dimensions of the image. numberOfColorBands should be = 3.
[rows, columns, numberOfColorBands] = size(rgbImage);
% Display the original color image.
subplot(2, 2, 1);
imshow(rgbImage);
axis on; grid on
title('Original Color Image');

採用された回答

Adam Danz
Adam Danz 2019 年 3 月 11 日
The funtion imshow() flips the y axis. To make the y-axis normal again.
ax = gca;
ax.YDir = 'normal';
However, your image will also flip its y direction.
  6 件のコメント
dpb
dpb 2019 年 3 月 12 日
Yes, I know what he wants...but sometimes we can't always have what we want and this is one of those times.
As said, you could fake it by simply writing the tick labels as the reverse or
hAx=gca;
ytk=hAx.YTick;
hAx.YTickLabel=max(ytk)-ytk;

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その他の回答 (1 件)

dpb
dpb 2019 年 3 月 11 日
編集済み: dpb 2019 年 3 月 11 日
imshow by default uses size() of the image x- and y- dimensions +/-0.5 as the axis x- and y-limits. The data are plotted on the axes from 1:Nx and 1:Ny so If you actually make the limits to be 0, you'll have a little background area outside the actual image data.
And, it always shows images with origin at top left. You can flip the axes, but unless you also flip() the image data in the y-direction, the image will be displayed upside down.
imshow(flipud(rgbImage)) % show the image in reversed y-direction
hAx=gca; % the parent axes handle
hAx.YDir='normal'; % invert the axis to go from bottom up so is displayed right side up
  2 件のコメント
Adam Danz
Adam Danz 2019 年 3 月 11 日
imshow(flipupdn(rgbImage))
should be
imshow(flipud(rgbImage))
dpb
dpb 2019 年 3 月 11 日
編集済み: dpb 2019 年 3 月 11 日
good catch....I'll fixup the answer. I knew it "looked funny" but couldn't see just what...

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