The following code is not working

function [x,h] = Transient()
%% Initialization
theta = 50; % degrees - angle of repose of material
n = 8; % r.p.m. - rotation speed of tube
rho = 660; % kg/m3 - bulk density of material
R = 0.075; % m - inner radius of tube
beta = 3; % degrees - inclination angle of kiln
L_tube = 2; % m,lenght of the kiln
mass_flow_rate = 0.5; % kg/min - mass flow of material
x_points=100;
t_points=100;
%% Solving initial condition
xspan_1=[0 L_tube];
h0 = 0.000001; % initial condition (bed height at the discharge end - average of particle diameter)
sol = ode45( @saeman_bed ,xspan_1 ,h0); % solver for unsteady nonliner ode
x = linspace(0,L_tube,x_points);
u0 = deval(sol,x)
%% Solving with pdepe
m = 0;
x = linspace(0,1,x_points);
t = linspace(0,2,t_points);
sol = pdepe(m,@pdex1pde,@(x0)pdex1ic(x0,x,u0),@pdex1bc,x,t);
% Extract the first solution component as u.
u = sol(:,:,1)
function [c,f,s] = pdex1pde(x,t,u,DuDx)
f_H=power((2*u/R)-power(u,2)/power(R,2),0.5);
u_T=2*pi*n*R;
c = f_H;
f = (u_T*R*cotd(theta))*power(f_H,1.5).*DuDx;
s = u_T*tand(beta)/sind(theta)*f_H.*power(1-f_H,0.5).*DuDx;
end
% --------------------------------------------------------------
function u0 = pdex1ic(x0,x,u)
u0 = interp1(x,u,x0);
% -------------------------------
end
function [pl,ql,pr,qr] = pdex1bc(xl,ul,xr,ur,t)
pl = ul+0.000001 % exit
ql = 0;
pr =(3*tan(deg2rad(theta))* mass_flow_rate/rho) / (4*pi*n*power(R,3)) * power((2*ul/R) - power((ul/R),2),(-3/2)) -tan(deg2rad(beta))/cos(deg2rad(theta));
qr = -1;
end
%% function for initial condition
function [dhdx,h] = saeman_bed (z,h);
dhdx = (3*tan(deg2rad(theta))* mass_flow_rate/rho) / (4*pi*n*power(R,3)) * power((2*h/R) - power((h/R),2),(-3/2)) -tan(deg2rad(beta))/cos(deg2rad(theta));
end
end

8 件のコメント

Matt J
Matt J 2019 年 1 月 2 日
What indication is there that it is not working?
MINATI
MINATI 2019 年 1 月 2 日
Dear Matt
the following error occurs while running the code
Error using pdepe
Too many input arguments
in
sol = pdepe(m,@pdex1pde,@(x0)pdex1ic(x0,x,u0),@pdex1bc,x,t);
Rik
Rik 2019 年 1 月 2 日
Have you tried separating out the anonymous functions from the call to pdepe? Because this syntax seems fine, even back to R2012b.
Also, could you copy the full error message (i.e. all the red text)? It may provide an indication of where the solution might be.
MINATI
MINATI 2019 年 1 月 3 日
編集済み: MINATI 2019 年 1 月 3 日
Ans to your qn
Have you tried separating out the anonymous functions from the call to pdepe?
NO, Actually dont know how to do
Also, could you copy the full error message (i.e. all the red text)? It may provide an indication of where the solution might be.
YES
Rik
Rik 2019 年 1 月 3 日
What I mean is replacing this
sol = pdepe(m,@pdex1pde,@(x0)pdex1ic(x0,x,u0),@pdex1bc,x,t);
with this
pdefun=@pdex1pde;
icfun=@(x0)pdex1ic(x0,x,u0);
bcfun=@pdex1bc,x,t);
sol = pdepe(m,pdefun,icfun,bcfun,x,t);
And where is the full error text?
MINATI
MINATI 2019 年 1 月 3 日
編集済み: MINATI 2019 年 1 月 3 日
While run, error is
Error: bcfun=@pdex1bc,x,t);
Unbalanced or unexpected parenthesis or bracket.
After removing last bracket
bcfun =
function_handle with value:
@Transient/pdex1bc
x = (DISPLAYS SOME VALUES)
Error using pdepe
Too many input arguments.
Error in (line 27)
sol = pdepe(m,pdefun,icfun,bcfun,x,t);
>> What to do now?
Rik
Rik 2019 年 1 月 3 日
I see I made a copy-paste error, so indeed you should fix that line to
bcfun=@pdex1bc;
But your error seems to be a bit deeper. Can you show the output of
which pdepe -all
I'm suspecting somehing is shadowing the correct function, because your input looks like it should be valid, but it still returns this error.
MINATI
MINATI 2019 年 1 月 4 日
By running
which pdepe -all
The following output came:
C:\Users\HP\pdepe.m
C:\Program Files\MATLAB\R2016b\toolbox\matlab\funfun\pdepe.m % Shadowed

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回答 (1 件)

madhan ravi
madhan ravi 2019 年 1 月 4 日

0 投票

You have file named pdepe please rename it or delete it becuase it‘s shadowing the inbuilt function pdepe()

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2019 年 1 月 2 日

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2019 年 1 月 4 日

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