error:An array for multiple LHS assignment cannot contain expressions.

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Yi-Le Li
Yi-Le Li 2018 年 11 月 18 日
編集済み: madhan ravi 2018 年 11 月 18 日
Error: File: Q7.m Line: 12 Column: 2
What does the error mean?
I'm using Matlab to solve Mechanism problems,and here is my code.
I'm pretty sure that it's not InverseRR's problem.I have used that function in other problems ,and it worked.
Hope that somebody who good at it could help me,please><
clc
clear
a1 = 15 ; a2 = 30 ; a3 = 20 ; a4 = 30 ; alpha = 30;
Xq = 50 ; Yq = 8 ; Xr = 70 ; Yr = 8;
dXa = 10 ; dYa = 0;
Xa = 20 ;Ya = a1 ;
I = 1;
BC = sqrt(a3^2 + a4^2 - 2 * a3 * a4 * cos(alpha)) ;
[(theta04),(theta02),dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR(Xq,Yq,a3,a2,Xa,Ya,dXa,dYa,ddXa,ddYa,I);
theta2 = theta02 - 180;
theta4 = theta04 - alpha;
  7 件のコメント
madhan ravi
madhan ravi 2018 年 11 月 18 日
@Yi no you will still have error see my answer below
Yi-Le Li
Yi-Le Li 2018 年 11 月 18 日
@Stephen Cobeldick
>> Q7
Error: File: Q7.m Line: 12 Column: 2
An array for multiple LHS assignment cannot contain expressions.

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採用された回答

Bruno Luong
Bruno Luong 2018 年 11 月 18 日
編集済み: Bruno Luong 2018 年 11 月 18 日
Remove the parenthesis
[theta04,theta02,dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR...
  3 件のコメント
Bruno Luong
Bruno Luong 2018 年 11 月 18 日
it means you get the error! Parenthesis on LHS is not valid syntax so why you ask me the meaning?
Yi-Le Li
Yi-Le Li 2018 年 11 月 18 日
Oh!!Got it !! I'm a new matlab learner.
Thank you so much for helping me solve it !!

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その他の回答 (1 件)

madhan ravi
madhan ravi 2018 年 11 月 18 日
編集済み: madhan ravi 2018 年 11 月 18 日
The problem in your code was you put comma ( , ) instead of semicolon ( ; )
Reason see mldivide
a1 = 15 ; a2 = 30 ; a3 = 20 ; a4 = 30 ; alpha = 30;
Xq = 50 ; Yq = 8 ; Xr = 70 ; Yr = 8;
dXa = 10 ; dYa = 0;
Xa = 20 ;Ya = a1 ;
I = 1;
ddXa=3; %fake data change it to your value
ddYa=5; %fake data change it to your value
BC = sqrt(a3^2 + a4^2 - 2 * a3 * a4 * cos(alpha)) ;
%|------||------|----error was here
[theta04,theta02,dtheta4,dtheta2,ddtheta4,ddtheta2] = InverseRR(Xq,Yq,a3,a2,Xa,Ya,dXa,dYa,ddXa,ddYa,I);
theta2 = theta02 - 180;
theta4 = theta04 - alpha;
function[PHI,PSI,dPHI,dPSI,ddPHI,ddPSI] = InverseRR(Xq,Yq,c,b,Xa,Ya,dXa,dYa,ddXa,ddYa,I)
X = Xa - Xq;
Y = Ya - Yq;
A = 2 * c* Y;
B = 2 * c * X;
C = X^2 + Y^2 + c^2 - b^2;
t1 = (A + sqrt(A^2+B^2-C^2))/(C+B);
t2 = (A - sqrt(A^2+B^2-C^2))/(C+B);
if (I == 1)
t = t1;
else
t = t2;
end
PHI = 2*atan(t);
U = (X- c*cos(PHI))/b;
V = (Y- c*sin(PHI))/b;
PSI = atan2(V,U);
Xb = c*cos(PHI);
Yb = c*sin(PHI);
%%% Inverse Velocity%%%
dX = dXa;
dY = dYa;
D = [ -c * sin(PHI) -b * sin(PSI); c * cos(PHI) b * cos(PSI) ];
% ^--------- error was here
E = [ dX;
dY ];
F = D \ E ;
dPHI = F(1,1);
dPSI = F(2,1);
%%% Inverse Acceleration %%%
ddX = ddXa;
ddY = ddYa;
G = [ -c * sin(PHI) -b * sin(PSI); %error was here
c * cos(PHI) b * cos(PSI) ];
H = [ ddX + c * cos(PHI) * dPHI ^2 - b * cos(PSI) * dPSI ^2 ; %error was here
ddY + c * cos(PHI) * dPHI ^2 - b * sin(PSI) * dPSI ^2 ] ;
I = G \ H;
ddPHI = I(1,1);
ddPSI = I(2,1);
PHI = PHI / pi * 180;
PSI = PSI / pi * 180;
end
  1 件のコメント
Stephen23
Stephen23 2018 年 11 月 18 日
"The problem in your code was you put comma ( , ) instead of semicolon ( ; )"
Where? And why is this a problem?

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