fprintf the contents of a vector

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Obadah M.
Obadah M. 2018 年 11 月 17 日
コメント済み: madhan ravi 2018 年 11 月 18 日
Hello,
As the title suggests, I want to display the contents of a vector in a fprintf command. I have read several posts about sprintf function and had no luck.
My current solution is this..... Is there any more efficient way to right it with less lines of codes?
fprintf('My first vector: ')
fprintf('%d ', vector1)
fprintf('\n')
fprintf('My second vector: ')
fprintf('%d ', vector2)
fprintf('\n')
fprintf('My third vector: ')
fprintf('%d ', vector3)
fprintf('\n')

回答 (3 件)

madhan ravi
madhan ravi 2018 年 11 月 17 日
編集済み: madhan ravi 2018 年 11 月 17 日
EDITED
But this method is much faster than yours:
g=sprintf('%d ', vector1);
fprintf('Vector1 : %s\n', g)
g=sprintf('%d ', vector2);
fprintf('Vector2 : %s\n', g)
g=sprintf('%d ', vector3);
fprintf('Vector3 : %s\n', g)
Ran a loop to check the speed:
tic
for i = 1:100000
vector1 =1:10;
g=sprintf('%d ', vector1);
fprintf('Vector1 : %s\n', g)
end
toc
Elapsed time is 10.538184 seconds.
tic
for i = 1:100000
vector1 =1:10;
fprintf('Vector1 : ')
fprintf('%d ', vector1)
fprintf('\n')
end
toc
Elapsed time is 15.363047 seconds.
  4 件のコメント
Image Analyst
Image Analyst 2018 年 11 月 17 日
On my computer, my code below takes
Elapsed time is 0.000407 seconds.
so speed doesn't seem to be an issue worth worrying about.
madhan ravi
madhan ravi 2018 年 11 月 18 日
True sir Image Analyst :)

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Walter Roberson
Walter Roberson 2018 年 11 月 17 日
Fewer lines of code but not necessarily any more efficient in execution:
fprintf( ['My first vector: ', repmat('%d ', 1, numel(vector1)), '\n'], vector1);

Image Analyst
Image Analyst 2018 年 11 月 17 日
You could get rid of two of the fprintf's:
fprintf('My first vector: ')
fprintf('%d ', vector1)
fprintf('\nMy second vector: ')
fprintf('%d ', vector2)
fprintf('\nMy third vector: ')
fprintf('%d ', vector3)
fprintf('\n')

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