EXP function with imaginary number
古いコメントを表示
I am working with Matlab to reproduce SAR image by radar. But when I calculate the EXP function, the result is so different.
>> exp(0.000000000000000e+00 - 8.378507193591911e+06i)
ans =
0.5122 + 0.8588i
>> exp(0.000000000000000e+00 - 8.378522834360446e+06i)
ans =
-0.4534 - 0.8913i
I do not know why in the result, one is negative, and one is positive. Please help me with this. Thank you so much for your consideration.
3 件のコメント
Torsten
2018 年 9 月 3 日
exp(it) = cos(t)+i*sin(t)
So why are you surprised about the result ?
Best wishes
Torsten.
There is nothing surprising about those results, their difference is more than 2*pi:
>> L = 8.378507193591911e+06;
>> R = 8.378522834360446e+06;
>> R-L
ans = 15.641
You can plot this easily, and see how that range includes real and imaginary parts that are both positive and negative:
>> V = linspace(L,R,100);
>> E = exp(complex(0,V));
>> plot(E,'-*')

>> M = [real(E(:)),imag(E(:))];
>> plot(V,M,'-*')

Nguyen Trung Kien
2018 年 9 月 4 日
採用された回答
その他の回答 (0 件)
カテゴリ
ヘルプ センター および File Exchange で Logical についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!