Indexing with different sized vectors
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I currently have one vector (49x1) which contains time stamp values - i.e. the first 3 numbers of the vector idx = [1;2013;5045] are associated with specified points in time. I also have another vector (X) which has numerical values for each given point in time - i.e. if I want to the find the value at the specified time point I can just index straight into this. However, I want to find the mean of subsequent points from the initial timestamps specified above and over differing durations. For example I would like to find the mean of the 200 points after the first time stamp and the mean of 350 points after the second timestamp. Essentially I have a third vector - duration = [200;350;255] - specifying the durations for which I want to calculate.
I have currently got the function set up but only returns one value as opposed to one for each idx:
function MeanX = AvgValues(X,Idx,duration)
Duration = Idx + duration;
MeanX = mean(X(Idx:Duration,:),1,'omitnan');
end
6 件のコメント
dpb
2018 年 8 月 13 日
編集済み: dpb
2018 年 8 月 13 日
Output = zeros(size(length(Idx)))
should be
Output = zeros(size(Idx));
and there's no need for the secondary Count indexing variable; it's the same as k so mayst as well just use it...
function Output = Val(X,Idx,Dur)
Output = zeros(size(Idx));
for k = 1:length(Idx)
duration = Idx(k)+(Dur);
t = Idx(k):duration;
Output(k) = nanmean(X(t,:));
end
end
回答 (1 件)
dpb
2018 年 8 月 11 日
編集済み: dpb
2018 年 8 月 11 日
arrayfun(@(ix,n) mean(X(ix:ix+n-1),'omitnan'), Idx,Duration);
Alternatively, instead of generating the start index and count, build a grouping variable and use findgroups, splitapply or discretize...actually, iiuc, you may have the bin edges already for the latter with your indexing vector.
0 件のコメント
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