Interpolation of 3D point data
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Hello, I have a nx5 matrix where column 3, 4 and 5 are x,y,z 3D points respectively. I was wondering how I would interpolate (smooth) this 3D data. Many thanks
4 件のコメント
Walter Roberson
2016 年 4 月 20 日
What properties does the curve need to have? Are you looking for a spline fit? A pchip fit?
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John D'Errico
2016 年 4 月 29 日
編集済み: John D'Errico
2016 年 4 月 29 日
You can use my interparc tool, as found on the file exchange. It is designed to solve exactly this problem, in 2 or more dimensions.
xyz = interparc(1000,x,y,z,'spline');
xyz will be a 1000x3 array, where each row is an interpolated point on the curve.
Of course, you can do the interpolation in other ways. If you want to do the work in MATLAB yourself in much the same way as you tried to do it:
t = [0;cumsum(sqrt(diff(x).^2+diff(y).^2+diff(z).^2))];
t = t/t(end);
ti = linspace(0,1,1000);
xx = spline(t,x,ti);
yy = spline(t,y,ti);
zz = spline(t,z,ti);
The above solution, which uses a cumulative piecewise linear arclength as the parameter for interpolation, deals more properly with points that are not uniformly spaced.
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その他の回答 (2 件)
Walter Roberson
2016 年 4 月 20 日
It looks to me as if you likely want a scattered interpolant.
shellmcg
2016 年 4 月 28 日
1 件のコメント
John D'Errico
2016 年 4 月 28 日
編集済み: John D'Errico
2016 年 4 月 29 日
I'm sorry, but this answer is just a poor way of solving the problem, presuming the points are somehow equally spaced. Use of a spline as was done here can cause some strange artifacts.
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