datetime format with T time demarcation

I have data that I've read in with datetime format that includes a T such as:

>> ais_data.BaseDateTime(3)

ans =

datetime

2023-08-01T11:07:56

If I change the value, how do I format the answer. For example, I would like to increment the minute, like such 2023-08-01T11:08:56

However, this results in the following error

>> datetime(2023-08-01T11:08:56)

datetime(2023-08-01T11:08:56)

↑

Error: Unexpected 'T11'. Check for missing multiplication operator.

How do make a datetime number like the one I'm seeing in the example at the top?

[Stephen23]

dt1 = datetime(2023,8,1,11,07,56, "Format","yyyy-MM-dd'T'HH:mm:ss")

dt1 = datetime
   2023-08-01T11:07:56

dt2 = dt1 + minutes(1)

dt2 = datetime
   2023-08-01T11:08:56

Answer 1

[dpb]

You're trying to convert a string representation so it has to be a string variable of some type... (+)

datetime('2023-08-01T11:08:56')

ans = datetime
   01-Aug-2023 11:08:56

If you have a datetime variable already, then increment it instead of trying to convert..

ais_data.BaseDateTime=datetime('2023-08-01T11:07:56')

ais_data = struct with fields:
    BaseDateTime: 01-Aug-2023 11:07:56

newDateTime=ais_data.BaseDateTime+minutes(1)

newDateTime = datetime
   01-Aug-2023 11:08:56

(+) If you have a value as datetime, to convert the string representation would be

ais_data.BaseDateTime.Format='yyyy-MM-dd''T''HH:mm:ss';  % default format doesn't include T
date_str=string(ais_data.BaseDateTime)

date_str = "2023-08-01T11:07:56"

datetime(date_str)

ans = datetime
   01-Aug-2023 11:07:56