Integer conversion without precision loss for literal function inputs
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The function uint64 can take a literal input that is not representable by double and convert without precision loss, like
uint64(7725400999518902274)
Unfortunately, this functionality does not seem to extend to a function with an argument block and type validation.
function test(a)
arguments
a (1,1) uint64
end
disp(a)
end
test(7725400999518902274)
I would have to do
test(uint64(7725400999518902274))
Does anyone know if there is a trick to get this functionality or I am otherwise missing something?
4 件のコメント
uint64(double(7725400999518902274))
uint64(7725400999518902274)
Unfortunately, this functionality does not seem to extend to a function with an argument block and type validation.
The argument block isn't the issue. Here's the same problem without it:
test(7725400999518902274)
function test(a)
a=uint64(a);
disp(a)
end
"The function uint64 can take a literal input that is not representable by double and convert without precision loss"
That is not true, it can do that within [0, 2^64-1]
uint64(123456789012345678901)
uint64(2^64-1)
uint64(2^64+1)
AB
2025 年 11 月 20 日
採用された回答
その他の回答 (1 件)
Walter Roberson
2025 年 11 月 21 日
2 投票
Does anyone know if there is a trick to get this functionality
There is no way of doing that.
Any way of doing that would have to affect the inputs at parse time. However, arguement blocks do not affect parse time. Arguement blocks apply conversions to whatever input was passed in. By the time the arguement block processing is applied, the parameter has already been parsed as double precision.
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