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How to find the coordinate of the point on (180) contour line when y(max)?

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ly
ly 2024 年 1 月 24 日
編集済み: Matt J 2024 年 1 月 24 日
How to find the coordinate of the point on (180) contour line when y(max)?
Code of the contour line:
clear
x = 0:0.1:3;
y = -2:0.1:3;
[X,Y] = meshgrid(x,y);
Z = 1000*(X.*exp(-X.^2-Y.^1));
contour(X,Y,Z,[90 180],'ShowText','on')

回答 (2 件)

John D'Errico
John D'Errico 2024 年 1 月 24 日
Easy.
  1. Use contourc to find that specific contour. It will be a piecewise linear curve.
  2. Find the point where y is maximum. That will also tell you the x coordinate at that point.
  1 件のコメント
Stephen23
Stephen23 2024 年 1 月 24 日
Extracting and working with the data from the CONTOURC output matrix is rather... tedious and fiddly.
There are several wrappers on FEX to make it easier to work with that data, e.g. :

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Matt J
Matt J 2024 年 1 月 24 日
編集済み: Matt J 2024 年 1 月 24 日
You could do the calculus, or use the Symbolic toolbox to help you.
syms x y z(x,y)
z=1000*(x.*exp(-x.^2-y.^1));
G=gradient(z);
assume(x>0);
xy_max=solve([G(1)==0, z==180]), %location of max point
xy_max = struct with fields:
x: 2^(1/2)/2 y: - log((9*2^(1/2))/50) - 1/2

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