Sorting of column 'folder' present in 'struct'

I have such a 'struct' and I want to make the column 'folder' in order. How can I do this?

[Jonas]

i don't understand, the column folder is already sorted correctly?

[Alberto Acri]

@Jonas

Lines 4-5-6 (where '\GLOBAL\DATA 11' is listed) I would like to have them at the bottom of the list (after '\GLOBAL\DATA 6')

[Stephen23]

Another approach is to download NATSORTFILES here:

https://www.mathworks.com/matlabcentral/fileexchange/47434-natural-order-filename-sort

unzip it and then use it like this:

A = 'C:\Users\Alberto\Desktop\GLOBAL';
B = dir(fullfile(A,'DATA*','*'));
B = natsortfiles(B,[],'rmdot','noext');

Answer 1

[Adam Danz]

Sounds like you want natural order sorting. There are some File Exchange submissions that do this (example). But if the format you shared is consistent across all paths, it would also be easy to use regular expressions to extract the ending numeric values and then sort those values.

This would have been easier to demonstrate if the paths were provided as text rather than a screenshot.

str = 'C:\Users\me\folderOne\folder2\docs\Data 11';
nstr = regexp(str,'\d+$','match','once');
n = str2double(nstr)

n = 11

[~, sortidx] = sort(n)

sortidx = 1

Then use sortidx to sort whatever you're sorting.

[Alberto Acri]

I thank you for your answer @Adam Danz. I don't quite understand how to apply them to my code.

I am using these lines of code:

A = 'C:\Users\Alberto\Desktop\GLOBAL';
B = dir(fullfile(A,'DATA*','*'));
B(ismember({B.name},{'.','..'})) = [];

Within the GLOBAL folder are several "DATA #" folders where # is a number from 1 to 50.

Within each "DATA" folder there are 3 folders "a", "c" and "s".

The "DATA #" folders I would like them in order.

[Adam Danz]

The variable str in my answer is just an example of 1 path. In your case, you'll define str as

str = {B.folder};

then you'll use sortidx from my answer B

B_sorted = B(sortidx);