use f=@(x) as an argument of a function.m
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I have the function
function [ k ] = New_Raph( f,df,x,tol)
x_old =x;
x=1000;
while abs(x_old-x) > tol
x_old = x;
delta=-f(x)/df(x);
x= x-delta;
end
k=x;
end
And i want to calculate in a new .m file:
f=@(x) x.^5-0.4475.*x.^4-3.1.*x.^3+3.085.*x.^2-0.962.*x+0.0943;
df1=@(x) 5.*x.^4-1.79.*x.^3-9.3.*x^2+6.17.*x-0.962;
New_Raph(@f1,@df1,0,0.1)
What is wrong?
0 件のコメント
採用された回答
per isakson
2015 年 3 月 13 日
編集済み: per isakson
2015 年 3 月 13 日
Replace
New_Raph(@f1,@df1,0,0.1)
by
New_Raph(f,df1,0,0.1)
f or f1 - a typo?
 
Addendum triggered by   It did not work
Try this example
>> my_sin = @(x) sin(x)
my_sin =
@(x)sin(x)
>> arrayfun( my_sin, pi/6*[1,2,3] )
ans =
0.5000 0.8660 1.0000
>> arrayfun( @sin, pi/6*[1,2,3] )
ans =
0.5000 0.8660 1.0000
and
>> arrayfun( @my_sin, pi/6*[1,2,3] )
Error: "my_sin" was previously used as a variable, conflicting with its use
here as the name of a function or command.
2 件のコメント
Stephen23
2015 年 3 月 13 日
"It did not work" does not tell us what happened when you tried it: was there an error message, unexpected values or something else?
It should work, according to the information that you have given us. Can you show us your exact code?
その他の回答 (1 件)
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