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Given a center, sum adjacent pixels

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MementoMori
MementoMori 2022 年 10 月 3 日
編集済み: Matt J 2022 年 10 月 3 日
Hi, suppose I have a matrix A and I have a center (for example (10.3,14.6)). Now I want to calculate the value of the center in this way
value = w1*A(10,14) + w2*A(10,15) + w3*A(11,14) + w4*A(11,15)
w1, w2, w3, w4 are the values of the weigths that are proportional to the distance of the pixel from the center.
What is the most correct way to evaluate w1, w2, w3, w4? I want that the weigth of the pixel that is closer to the center higher and the weigth of the pixel that is farther to the center lower and so on.
My hyphotesis is something like this:
w1=0.7 * 0.4 ; w2=0.7*0.6; w3=0.3*0.4; w4= 0.3*0.6
Thanks
  6 件のコメント
dpb
dpb 2022 年 10 月 3 日
NB the weights above sum to 2 which will double the value...and "proportional" how (linear, quadratic, exponential, ...) and by what measure of "distance"?
MementoMori
MementoMori 2022 年 10 月 3 日
the sum of the weights is 1. 0.7*0.4 + 0.7*0.6 + 0.3*0.4 + 0.3*0.6 =1
I think linear proportional and I don't know for distance, what is the most suitable?

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回答 (1 件)

Matt J
Matt J 2022 年 10 月 3 日
編集済み: Matt J 2022 年 10 月 3 日
Use interp2:
value=interp2(A,14.3,10.6)

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