how to develope loop to save the 'n' elements from the vectors

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gourav pandey
gourav pandey 2021 年 9 月 15 日
コメント済み: Matt J 2021 年 9 月 15 日
clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements

回答 (2 件)

Matt J
Matt J 2021 年 9 月 15 日
It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.
  2 件のコメント
Matt J
Matt J 2021 年 9 月 15 日
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)

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Awais Saeed
Awais Saeed 2021 年 9 月 15 日
Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
A = 1×5
14 51 2 15 7
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
p1 = 14
p2 = 51
p3 = 2
p4 = 15
p5 = 7
  1 件のコメント
Stephen
Stephen 2021 年 9 月 15 日
Note that this is slower and more complex than simply using the vector directly.

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