MATLAB Answers

Error using length, Too many input arguments.

9 ビュー (過去 30 日間)
C A
C A 2021 年 8 月 30 日
コメント済み: Walter Roberson 2021 年 9 月 1 日
I have a bunch of data from animal cells at different times. j represents the time frame. I want to extract a field from my object and that field can either have one or two values. If I have one value, I want to extract the value as it is and if I have two values, I want to average them out. This is a snippet of my code.
if length(Obj.MatFile{cellnumber}{j},ExtractField)==2
Answer(icellnumber,i)=mean(Obj.MatFile{cellnumber}{j}.(ExtractField));
else
Answer(icellnumber,i)=Obj.MatFile{cellnumber}{j}.(ExtractField);
end
I keep getting the above error. Any help would be greatly appreciated. Thanks in advance.

採用された回答

Matt J
Matt J 2021 年 8 月 30 日
編集済み: Matt J 2021 年 8 月 30 日
The first line shouldn't have any commas.
  3 件のコメント
C A
C A 2021 年 8 月 31 日
Thank you. This helps a lot!

サインインしてコメントする。

その他の回答 (1 件)

Stephen
Stephen 2021 年 8 月 31 日
編集済み: Stephen 2021 年 8 月 31 日
if length(Obj.MatFile{cellnumber}{j}.(ExtractField))==2
But note that you do not need to check the length: taking the mean of one value simply returns that value, so in both cases you can simply do this (and not worry about how many values there are):
Answer(icellnumber,i) = mean(Obj.MatFile{cellnumber}{j}.(ExtractField));
and then get rid of the IF entirely.
  2 件のコメント
Walter Roberson
Walter Roberson 2021 年 9 月 1 日
"if there are more than two" -- use numel() instead of length() if you want to know how many values there are. length() has a slightly different meaning.

サインインしてコメントする。

製品


リリース

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by