change a cell having 3-dimenisional matrix into a 2-dimenisional matrix

Hi all,

I have a variable named "z" which has the 2-dimensional cell structure like following program:

for tt=1:3    
    for nn=1:4
        z{tt,nn}=rand(2,3,4);        
    end  
end

z =

    [2x3x4 double]    [2x3x4 double]    [2x3x4 double]    [2x3x4 double]
    [2x3x4 double]    [2x3x4 double]    [2x3x4 double]    [2x3x4 double]
    [2x3x4 double]    [2x3x4 double]    [2x3x4 double]    [2x3x4 double];

assume the value of z at tt=1 and nn=1 , i.e. z{1,1}, is qual below: z{1,1}

val(:,:,1) =
        0.8147    0.1270    0.6324
        0.9058    0.9134    0.0975

      val(:,:,2) =
          0.2785    0.9575    0.1576
          0.5469    0.9649    0.9706

      val(:,:,3) =
          0.9572    0.8003    0.4218
          0.4854    0.1419    0.9157

      val(:,:,4) =
          0.7922    0.6557    0.8491
          0.9595    0.0357    0.9340

z{2,1} =

      val(:,:,1) =
          0.6880    0.5716    0.8095
          0.2968    0.3162    0.3655

      val(:,:,2) =
          0.6988    0.9646    0.5982
          0.6334    0.2008    0.0837

      val(:,:,3) =
          0.5444    0.0407    0.7093
          0.8461    0.3294    0.8603

      val(:,:,4) =
          0.5009    0.4286    0.4730
          0.9948    0.2673    0.1608

z{3,1} =  

      val(:,:,1) =
          0.1589    0.7571    0.9669
          0.2683    0.6092    0.7733

      val(:,:,2) =
          0.5729    0.2871    0.0944
          0.4502    0.7524    0.1068

      val(:,:,3) =
          0.7349    0.5806    0.7137
          0.3546    0.2989    0.3605

      val(:,:,4) =
          0.7185    0.0837    0.0938
          0.9953    0.4682    0.7252

and so on.

I want to put all elements of z into a matrix and make a new matrix named "zz" whose size is 24*9. for example the zz(:, 1:3) is like below:

zz(:,1:3)=[0.8147    0.1270    0.6324;
           0.9058    0.9134    0.0975;
           0.2785    0.9575    0.1576;
           0.5469    0.9649    0.9706;
           0.9572    0.8003    0.4218;
           0.4854    0.1419    0.9157;
           0.7922    0.6557    0.8491;
           0.9595    0.0357    0.9340;
           0.6880    0.5716    0.8095;
           0.2968    0.3162    0.3655;
           0.6988    0.9646    0.5982;
           0.6334    0.2008    0.0837;
           0.5444    0.0407    0.7093;
           0.8461    0.3294    0.8603;
           0.5009    0.4286    0.4730;
           0.9948    0.2673    0.1608;
           0.1589    0.7571    0.9669;
           0.2683    0.6092    0.7733;
           0.5729    0.2871    0.0944;
           0.4502    0.7524    0.1068;
           0.7349    0.5806    0.7137;
           0.3546    0.2989    0.3605;
           0.7185    0.0837    0.0938;
           0.9953    0.4682    0.7252;]

How can I do it? following is any help whould be appreciated. Thanks in advance.

Answer 1

[Matt J]

 zz=reshape(   cat(2,z{:})    ,[],9);

[som]

thanks for your answer. I did it for my code but it didn't work. it dosn't protect the order of data in z. in your idea is there any other solution????

[Matt J]

I think you need to redo the description of what you want. There are 288 doubles total contained across z, yet you claim to want a final matrix zz that is 24x9, which would contain only 216 elements. We also cannot see what data order you want when you only show the first 3 columns of zz.

[som]

ok, thanks for your response. I have explained my question more clearly through a new question. you can see it soon. I would be thankful if you take a look at that question and give me your feedback.