Deleting empty variables from cell variables with respect to rows.

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RDG
RDG 2013 年 10 月 11 日
編集済み: Matt J 2013 年 10 月 11 日
Suppose, I have this code excerpt:
clc, clear, close all;
A{1}=[1,4,1,6,130,30,4;1,6,3,6,130,30,4;1,6,2,1,130,30,4;1,1,2,2,130,200,4;1,4,1,1,130,30,4;
1,2,2,2,130,100,4;2,4,1,4,75,30,4;2,6,1,4,75,30,4;2,4,5,2,75,30,4;2,2,3,2,75,100,4;
2,5,4,6,75,20,4;2,6,5,5,75,30,4;4,1,5,6,117,200,3;4,2,3,5,117,100,3;4,3,2,4,117,9,3;
4,2,3,1,117,100,3;4,5,3,1,117,20,3;4,1,2,6,117,200,3;4,2,2,3,117,100,3]
A{2}=[1,1,1,6,130,200,4;1,3,3,4,130,9,4;1,2,3,3,130,100,4;1,4,3,5,130,30,4;1,3,1,2,130,9,4;
1,1,3,4,130,200,4;2,6,3,5,75,30,4;2,6,3,6,75,30,4;2,1,3,2,75,200,4;2,6,1,5,75,30,4;
2,5,1,2,75,20,4;2,5,2,1,75,20,4;4,6,2,6,117,30,3;4,2,2,3,117,100,3;4,3,3,3,117,9,3;
4,6,5,2,117,30,3;4,6,2,3,117,30,3;4,6,3,3,117,30,3;4,3,5,2,117,9,3]
for i=1:length(A)
for j=1:19
filtered{i,j}=A{i}(ismember(A{i}(:,1),[j]),:);
end
end
The filtered content consists of 2x19 cells. I would like to remove the empty variables (The ones with []) from filtered. I tried this code,
A=filtered(~cellfun(@isempty,filtered))
But it merges the 2 rows into 1 column. I would like to maintain the existing row position. In other words, it should remove the empty cell variables based on its row.
How can I get about this?
  1 件のコメント
RDG
RDG 2013 年 10 月 11 日
Did a bit of tweaking. This may not be the best solution.
for i=1:length(A)
for j=1:19
filtered{j}=A{i}(ismember(A{i}(:,1),[j]),:);
end
newfiltered{i}=filtered(~cellfun(@isempty,filtered(:)));
end

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採用された回答

Matt J
Matt J 2013 年 10 月 11 日
編集済み: Matt J 2013 年 10 月 11 日
You can still do this
A=filtered(~cellfun('isempty',filtered)),
but reshape it afterward
A=reshape(A,2,[]);
assuming it will always be reshapeable into something 2xN.

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