フィルターのクリア

How can I apply an auto-correlation to a Radon Transformation?

2 ビュー (過去 30 日間)
Andrei
Andrei 2013 年 10 月 10 日
コメント済み: Matt J 2013 年 10 月 14 日
I have the following code
I = imread('img.jpg');
I = rgb2gray(I);
theta = 1:180;
[R,xp] = radon(I,theta);
how can I apply auto-correlation on this radon transformation on an image?
I have the following formula for auto-correlation which I want to apply:
where g(s,0) is the radon transformation. How can I implement this in Matlab? or is there an equivalent function that I can use?
Thank you in advance!

採用された回答

Matt J
Matt J 2013 年 10 月 10 日
編集済み: Matt J 2013 年 10 月 10 日
Just apply conv() or xcorr(), if you have it, to each of the columns of R. A simple for-loop will do.

その他の回答 (1 件)

Matt J
Matt J 2013 年 10 月 10 日
編集済み: Matt J 2013 年 10 月 10 日
You can also use Fourier methods, something like
c=ifft( fft(R).*conj(fft(R)) )
c=bsxfun(@rdivide,c,sum(R.^2,1));
  3 件のコメント
Bjorn Gustavsson
Bjorn Gustavsson 2013 年 10 月 14 日
Just shooting from the hip on this one. In principal the results should be the same, within numerical accuracies- but if you use xcorr it might give you some default weigthing of the different lags.
Matt J
Matt J 2013 年 10 月 14 日
The correlation/convolution, when implemented using ffts, is circulant. You will have to zero pad to make it equivalent to linear convolution.

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by