how to count no of zeros between ones

suppose my array is

a=[0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0]

output i want is

[2 4 4 1 2]

Answer 1

[Walter Roberson]

a=[0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0]

a = 1×21

0 0 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 0 1 0 0

starts = strfind([1 a], [1 0])

starts = 1×5

1 7 13 18 20

stops = strfind([a 1], [0 1])+1

stops = 1×5

3 11 17 19 22

stops - starts

ans = 1×5

2 4 4 1 2

[PRIYAM DEKA]

thanks

Answer 2

[Matt J]

Using the tools in this FEX submission,

https://www.mathworks.com/matlabcentral/fileexchange/78008-tools-for-processing-consecutive-repetitions-in-vectors

[~,~,output]=groupLims(groupTrue(~a),1)