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How to get quotient value after division without round off?

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Khushboo Singla
Khushboo Singla 2021 年 6 月 19 日
回答済み: Steven Lord 2021 年 6 月 19 日
I want to get quotient (only integer value) after division of two numbers without rounding off.
n1 = I1(i,j) +1;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2);
end
when n1 = 157 in first line :
then in fourth line after dividing by 2 , n1 is taking 79 (157/2 = 78.5) value
but i want n1 to take 78 value.
  2 件のコメント
dpb
dpb 2021 年 6 月 19 日
>> n1=157;
>> fix(n1/2)
ans =
78
>>
You've done something else you've not told us about first...like an intermediate store with a rounding operation, maybe.
Even in your code;
>> n1=157;for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix(n1/2)
end
n1 =
78
n1 =
39
n1 =
19
n1 =
9
n1 =
4
n1 =
2
n1 =
1
n1 =
0
>>

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採用された回答

Mouhamed Niasse
Mouhamed Niasse 2021 年 6 月 19 日
Hello,
I tried to execute your portion of code but, just as expected, n1 has the value 78 not 79 for me.
Try using the function 'floor' instead of 'fix', they normally give the same output for positive input values.
  1 件のコメント
Khushboo Singla
Khushboo Singla 2021 年 6 月 19 日
Thankyou so much. Though same problem persisted in my code BUT i got another solution
as I subtracted remainder(from third line) from the number(n1) everytime so that it will give only interger value after division as shown:
n = 157;
for k1= 0:7
l1(8-k1) = rem(n1,2);
n1 = fix((n1-l1(8-k1))/2)
end

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その他の回答 (1 件)

Steven Lord
Steven Lord 2021 年 6 月 19 日
If one or both of the numbers are stored as an integer type you could use the idivide function.
idivide(int16(157),2)
ans = int16 78

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