How to write and run while loop in app design?
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C= app.CollectionEditField.Value;
S= app.ServingEditField.Value;
app.cycle=0;
cycle_t=app.cycle;
app.FC=0;
F_C=app.FC;
app.F=0;
F_1 =app.F;
SC= S;
while F_C<=double(SC-0.000001))
F_1= double(S*C);
S= double(S-F_1);
F_C= double(F_C+F_1);
Fo= F_C;
cycle_o= (cycle_t+1);
end
app.CycleEditField.Value= cycle_o;
app.FInalCollectionEditField.Value= Fo;
8 件のコメント
dpb
2021 年 6 月 11 日
The posting could stand some context and explanation of just what is the problem, but...
C= app.CollectionEditField.Value;
S= app.ServingEditField.Value;
are both text values; I think you need a str2double() here and undoubtedly an error handler to catch any failure in the conversion.
That's the crystal ball talking lacking any other information to go on...
Shabaz Khan
2021 年 6 月 11 日
dpb
2021 年 6 月 11 日
So then is there a question here?
Shabaz Khan
2021 年 6 月 11 日
Cris LaPierre
2021 年 6 月 11 日
編集済み: Cris LaPierre
2021 年 6 月 11 日
It sounds like your while loop is running, but just not the way you expected. However, without some actual values, we can only guess what is happening. Could you supply what the initial and final values of S, C, cycle_o and Fo should be?
Shabaz Khan
2021 年 6 月 14 日
dpb
2021 年 6 月 14 日
F_C=0;
cycle_t=0;
S=15;
C=0.02;
SC=S;
while F_C <=SC-0.000001
F_1= S*C;
S= S-F_1;
F_C= F_C+F_1;
Fo= F_C;
cycle_o=cycle_t+1;
end
>> cycle_o
cycle_o =
1
>> F_C
F_C =
15.0000
>> SC
SC =
15
>>
I have no klew what you're trying to do here, but your first line in the while construct sets F_1 to the S*C product and then the control variable F_C is set to F_C+F_1 which is F_1 since F_C is initialized to zero. Thus, the inequality
F_C <= SC-eps
fails and the loop terminates.
Shabaz Khan
2021 年 6 月 14 日
回答 (1 件)
Shadaab Siddiqie
2021 年 6 月 15 日
From my understanding you are not able to run while loop in your code. I dont see anything wrong with the loop or with the code that you mentioned in the comment, I would advice you to check if the varaibles
C= app.CollectionEditField.Value;
S= app.ServingEditField.Value;
are as expected.
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