Concatenate 3-D matrix in a for loop

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Joana
Joana 2021 年 5 月 6 日
コメント済み: Stephen23 2021 年 5 月 6 日
Hi
I have 25 matrices of 3-D 150x66x1000. I need to concatenate them in a for loop to get an output of 3750x66x1000.
How can i do that.?
  1 件のコメント
Stephen23
Stephen23 2021 年 5 月 6 日
" I need to concatenate them in a for loop..."
Why do you need to use a FOR loop?
Using VERTCAT or CAT would be simpler and probably more efficient.

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Stephen23
Stephen23 2021 年 5 月 6 日
編集済み: Stephen23 2021 年 5 月 6 日

その他の回答 (2 件)

KSSV
KSSV 2021 年 5 月 6 日
A = rand(2,3,4) ;
B = rand(2,3,4) ;
C = cat(1,A,B)
  2 件のコメント
Joana
Joana 2021 年 5 月 6 日
Thanks for the comment. But can you please help me with the loop thing.?
KSSV
KSSV 2021 年 5 月 6 日
You have 25 matrices ... how they are named? How the data is?

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Sambit Supriya Dash
Sambit Supriya Dash 2021 年 5 月 6 日
With an example, I would like to answer this. Suppose, "a" is the given 3D Matrix
and "b" is the 2D matrix returns the concatenated "a"
a(:,:,1) = [1 2;3 4]; % a --> Given Tensor (3D Matrix) to be operated into matrix "b"
for i = 2:4
a(:,:,i) = a(:,:,i-1)+1; % Supposing elemental opeartion is incrementing element by 1
end
[x,y,z] = size(a); % Calculate the length of tensor in 3rd D
b = zeros(x,y*z);
for k = 1:z
for i = 1:x
for j = 1:y
b(i,j+2*(k-1)) = a(i,j,k); % Concatenating
end
end
end
% For Checking the Concatenation of 3D Elements
c = reshape(a,x,y*z);
if b == c
disp('CONCATENATION SUCCESSFUL')
disp(b)
else
disp('CONCATENATION FAILED')
end

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