How do I use matlab to plot a graph where the x,y axes do not intersect?

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cui,xingxing
cui,xingxing 2021 年 4 月 27 日
コメント済み: Adam Danz 2021 年 4 月 30 日
How can I use matlab to plot a graph where the x,y axes do not intersect? Similar to the image below, note that the bottom left corner does not cross.The x- and y-axes are shown with specified ranges
  5 件のコメント
Adam Danz
Adam Danz 2021 年 4 月 28 日
> So look out for future versions with more axes to customise and personalise
@cui, what does that mean?
cui,xingxing
cui,xingxing 2021 年 4 月 29 日
Oh, what I meant to say was that I hope that future versions will enhance the personalisation of axes properties.
PS: I am not very good at English, sorry

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採用された回答

Jonas
Jonas 2021 年 4 月 28 日
not elegant, but possible if i'm not mistaken:
fig=figure;
% amount of shift of x and y axis in normalized coordinates
dx=0.05;
dy=0.05;
plotAx=axes('Position',[0.1 0.1 0.85 0.85],'Color','none');
% create shifted y axis
yax=axes('Position',plotAx.Position-[dx 0 -dx 0],'Color','none','XColor','none');
yax.XGrid='off';
% create shifted x axis
xax=axes('Position',plotAx.Position-[0 dy 0 -dy],'Color','none','YColor','none');
xax.YGrid='off';
axes(plotAx); % set curr axis
% plot sample data
x=-2:0.1:2;
y=(x-1).^2+1;
plot(plotAx,x,y)
grid off;
linkaxes([plotAx,yax,xax]);
yticklabels([]);
xticklabels([]);
% remove rulers
plotAx.XColor='none';
plotAx.YColor='none';
  5 件のコメント
cui,xingxing
cui,xingxing 2021 年 4 月 30 日
@Adam DanzI'm very glad to hear that! But I personally think that these "basic issues" should be left to the mathworks development engineers, and that the new version should enhances these shortcomings.
Adam Danz
Adam Danz 2021 年 4 月 30 日
I'm not so sure disconnected axes is a very popular idea. What's the benefit of doing this, by the way? Curious.

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その他の回答 (1 件)

Bob Thompson
Bob Thompson 2021 年 4 月 27 日
Create your figure first, then create the axes. This will allow you to specify what they are before the data gets populated, and should allow you to fix their positions.
I have not looked at the documentation in enough detail to confirm it will do exactly what you want, but it should be in the axes command.
  2 件のコメント
cui,xingxing
cui,xingxing 2021 年 4 月 28 日
I can't find any customisation of axes properties related to axis position lengths etc. in the axes properties rulers, not in the documentation at the moment.
It would be nice to have a concrete and elegant code implementation.
Adam Danz
Adam Danz 2021 年 4 月 28 日
cui is correct here. There are no axes properties that can achive this. There are, however, undocumented ruler properties that can achieve at least some of it.

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