removing trailing zeros at the end of floating number

I m getting the numerical result with trailing zeros even after rounding of to few decimal places for eg.:- 3.265000000000 how do i remove those zeroes and just get the value as 3.265

Answer 1

[DGM]

Assuming this is for display purposes, try something like

fprintf('%6.3f\n',3.2653246546516)

gives

3.265

[Abhijit Sardar]

no i want to save the value without zeroes for further data processsing

[James Tursa]

The trailing 0's is an artifact of converting the binary floating point bit pattern into a decimal number for display purposes, so this is just a display issue. The number isn't stored in decimal so those decimal 0's you are worried about don't exist in the stored number. The stored number is using IEEE binary floating point format, not any decimal format. What are you doing with these numbers downstream in your code where you think these trailing 0's will cause you a problem?

Also, many decimal numbers can't be represented exactly in binary floating point anyway. So if you were to print out many more digits, there will be non-zero digits after some trailing 0's in the decimal conversion. This is the nature of using binary floating point for calculations.

[Abhijit Sardar]

but when i am copy pasting the data in text file trailing zeroes are still there

Answer 2

[Adam Danz]

format long
x = -3.265000000000;
str = sprintf('%g\n',x)

str = 
    '-3.265
     '

x = -3.2650000000001;
str = sprintf('%g\n',x)

str = 
    '-3.265
     '