Help with if statement in a calculation loop
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Hello,
I have a problem with a code. I want to calculate some numbers but I want to "limit" my results via a loop.
I want values <1 to be =1, values with >10 to be 10 and the others to be calculated from this equation:
x= x*1.3+0.5. I wrote this code but it is not use
x= 5 + randn * 0.5
if x < 1
x == 1
elseif x > 10
x == 10
else x > 3
x == 1.3* x -0.75
end
Where is the problem?
Thanking you in advance
2 件のコメント
Nino Wyssen
2021 年 4 月 12 日
I can see several problems here.
First, Matlab likes the lines to be finished with a semicolon, but this isn't necessary if you don't mind your programm outputting all the operations.
Then, you aren't assigning values. You are comparing them. To assign a new value to a variable you only need one equal sign.
Third, you can't use a condition for you else statment, if you only wnt to execute the command below u need to use another elseif.
From your description I suspect the following code does the right thing for you:
x= 5 + randn * 0.5;
if x < 1
x = 1;
elseif x > 10
x = 10;
else
x = 1.3* x -0.75;
end
even though I think it would be better to use a new variable for your result
x= 5 + randn * 0.5;
if x < 1
y = 1;
elseif x > 10
y = 10;
else
y = 1.3* x -0.75;
end
採用された回答
Stephen23
2021 年 4 月 12 日
The simplest and most efficient solution is to use MIN and MAX:
x = 5 + randn(5,7)*1.5;
x = x*1.3 + 0.5
x = min(max(x,1),10) % this is all you need.
0 件のコメント
その他の回答 (1 件)
Rik
2021 年 4 月 12 日
編集済み: Rik
2021 年 4 月 12 日
The problem is that you assume Matlab will process each element of x separately. Matlab will only do that if you use a loop.
An alternative is to use logical indexing to process x as an array.
L=x<1;
x(L)=1;
L=x>10;
x(L)=10;
L=x>3;
x(L)=1.3* x(L) -0.75;
4 件のコメント
Rik
2021 年 4 月 12 日
In that case you should use the code Stephen suggested.
If you have a piecewise function you can use the code I suggested.
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