How do i reconstruct a matrix???
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I have a matrix 2000x3 like this:
1 1 6
1 2 8
1 3 15
....
2 1 10
2 2 20
2 3 13
....
3 1 12
3 2 18
3 3 14
...
...
and i want to reconstruct like this:
1 1 6
1 2 8
1 3 15
....
2 3 13
2 2 20
2 1 10
....
3 1 12
3 2 18
3 3 14
...
...
Please help me..
3 件のコメント
Image Analyst
2013 年 6 月 24 日
編集済み: Image Analyst
2013 年 6 月 24 日
The middle group has the second column flipped. But that's not enough to figure out what needs to be done in general. And what does this have to do with Image Processing, like the tag says?
採用された回答
Andrei Bobrov
2013 年 6 月 25 日
a - your array
a1 = a;
n = unique(a(:,1));
for jj = 1:numel(n)
if rem(n(jj),2) == 0
t = a1(:,1) == n(jj);
a1(t,:) = flipud(a1(t,:));
end
end
その他の回答 (2 件)
Evan
2013 年 6 月 24 日
M(:,:,2) = flipud(M(:,:,2))
As an example:
M = rand(3,3,3); %random example 3d matrix
M(:,:,2) = flipud(M(:,:,2));
1 件のコメント
Evan
2013 年 6 月 26 日
In light of George's update in the below comment, this code does not do what he is asking for. http://www.mathworks.com/matlabcentral/answers/79846#comment_156778
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