Replacing n-d array elements based on pre-defined list
1 回表示 (過去 30 日間)
古いコメントを表示
Hi,
Suppose I have an n-d array of q unique integers. I want to replace the value of every element in this n-d array based on a list (q by 2 matrix) like this:
1 k
2 l
3 m
...,
which means that every element with value 1 in the n-d array is replaced by k, every element with value 2 is replaced by l, etc. k, l, m... are double-precision numbers.
What's the most efficient way of doing this? Obviously, one could loop through 1, 2, 3..., find their linear indices and set elements with those indices to k, l, m... I would like to do this faster, if possible.
Any ideas are appreciated.
0 件のコメント
採用された回答
その他の回答 (1 件)
Roger Stafford
2013 年 6 月 11 日
編集済み: Roger Stafford
2013 年 6 月 11 日
If it isn't assumed that vector 'l' contains successive integers starting with 1, then you could do this:
[tf,loc] = ismember(V(:),l);
V(tf) = k(loc(tf));
where 'k' is the vector of values to replace those in 'l' and where 'V' is the n dimensional array. ('l' is the lowercase 'L', not the numeral.)
2 件のコメント
Roger Stafford
2013 年 6 月 11 日
My apologies. I misread your two vectors as being named 'l' and 'k'. My code still works whatever you name them provided they are the same length. It doesn't matter whether they contain integers or non-integers. Whenever an element in V is equal to one in 'l' (or whatever you call it,) it is replaced by the corresponding element in 'k' (or whatever you call that one.)
参考
カテゴリ
Help Center および File Exchange で Logical についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!