フィルターのクリア

how can I write code to reach my goal as figure below?

1 回表示 (過去 30 日間)
kimy
kimy 2021 年 3 月 28 日
コメント済み: kimy 2021 年 4 月 4 日
Hi guys,
P is a matrix with dimension i*j; n is an integer. How can I write this formula in matlab? Thanks.
  2 件のコメント
Adam Danz
Adam Danz 2021 年 3 月 28 日
What part are you having trouble with? How can we help without doing it for you?
kimy
kimy 2021 年 3 月 29 日
Hello Adam, in fact I was trying a loop to give the value for rij, also Ci and Vi However, the code I wrote must be wrong. Could you please give me some suggestions? Thanks.
for i=1:n
for j=1:n
for k=1:n
syms k
R(i,j)=symprod(P(i,k)*P(k,j),k,1,n)^(1/n)
C(i)=(symprod(R(i,k),k,1,n))^(1/n)
V(i)=C(i)/sum(C(k),k,1,n);
end
end
end

サインインしてコメントする。

回答 (1 件)

Adam Danz
Adam Danz 2021 年 3 月 29 日
編集済み: Adam Danz 2021 年 3 月 29 日
> in fact I was trying a loop to give the value for ri
r is an existing matrix. i and k are just indices. So the value of ri is just r(i,:) and the value of rik is r(i,k).
> also Ci and Vi
What's Vi?
For C, is this what you're looking for?
%n = ?? % scalar
%r = ?? % size nxn
C = nan(1,n);
for i = 1:n
C(i) = nthroot(prod(r(i,1:n)),n);
end
which is the same as
%n = ?? % scalar
%r = ?? % size nxn
C = nthroot(prod(r(1:n,1:n),2),n)
  3 件のコメント
Adam Danz
Adam Danz 2021 年 3 月 29 日
I don't follow what you're saying and it seems like the question and background information is changing with each comment. I've already reached my allotted volunteer time for the day but I can check back later to see if there is a crystal clear question with all the needed background information.
kimy
kimy 2021 年 4 月 4 日
Sorry, now I solved the problem. But the following comlicated formula seems not so easy to write, could you please give me some suggestions? Thanks.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by