How to get the string form of an anonymous function?

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Richard
Richard 2021 年 2 月 16 日
コメント済み: Richard 2021 年 2 月 16 日
I was thinking about creating a function, which automatically creates plot, data, etc. This function is supposed to be an aid for solving differential equations with numerical methods.
The function is:
function [x,yf,yg]=graphing(f,g,interval)
x = linspace(interval(1),interval(end),80);
yf = f(x);
yg = g(x);
plot(x,yf,'g',x,yg,'b');
tf = 'f(x)=';
tg = 'g(x)=';
legend(tf,tg);
end
And the command could be:
interval = [0 4];
f = @(x) exp(-0.5*x);
g =@(x) sin(2*x);
[x,yf,yg] = graphing(f,g,interval)
There is a way to get the string form of the functional notation for the anonymous function, so that it is possible having in legend the exact function form? It could help me for orientation, even if it is not necessary. Just as a matter of interest.
Thank you in advance.

採用された回答

Fangjun Jiang
Fangjun Jiang 2021 年 2 月 16 日
編集済み: Fangjun Jiang 2021 年 2 月 16 日
f = @(x) exp(-0.5*x);
>> func2str(f)
ans =
'@(x)exp(-0.5*x)'
Or, provide your string, use str2func()
  1 件のコメント
Richard
Richard 2021 年 2 月 16 日
Thank you, it worked :)

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