Why do we need to flip the kernel in 2D convolution?
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Why do we need to flip the kernel in 2D convolution in the first place? What's the benefit of this? So, why can't we leave it unflipped? What kind of terrible thing can happen if you don't flip it?
SEE: "First, flip the kernel, which is the shaded box, in both horizontal and vertical direction"
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Image Analyst
2013 年 5 月 2 日
編集済み: Image Analyst
2013 年 5 月 2 日
1 投票
It doesn't need to be flipped, at least not by you. You pass in the array and the flipping is done internally, automatically, because that's the definition of convolution. If it didn't flip, it would be correlation, not convolution. If you flipped it before passing it into conv2(), then you'd be doing a correlation instead of a convolution because the internal flip in counteracted by your advance manual flip. If you want, you can use imfilter() or xcorr2() which do no flip internally.
3 件のコメント
Adnan Khan
2017 年 9 月 18 日
How flipping is done internally? though it is clear from the formula that it is done but how can we explain this in simple and concise words...
Image Analyst
2017 年 9 月 18 日
Flip it left to right using fliplr(), then flip it top to bottom with flipud().
Webi Dabuse
2020 年 9 月 29 日
Or you can just rotate it by 180 degrees. rot90(image,2)
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