Replacing a for loop with matrix multiplication
3 ビュー (過去 30 日間)
古いコメントを表示
In the problem I have here, x is a 2x300 matrix and SIG is a 2x2 matrix.
What I'm looking for is a 1x300 vector, where the ith entry corresponds to x(:,i)'*inv(SIG)*x(:,i). I've written this out in a for loop below:
ans = zeros(1,size(x,2));
for i = 1:size(x,2)
ans(i) = x(:,i)'*inv(SIG)*x(:,i);
end
but I think there must be a way to make this more efficient with some sort of matrix multiplication--I just can't figure it out.
Any help appreciated!
1 件のコメント
採用された回答
James Tursa
2021 年 2 月 1 日
編集済み: James Tursa
2021 年 2 月 1 日
result = sum(x.*(inv(SIG)*x));
or
result = sum(x.*(SIG\x));
1 件のコメント
その他の回答 (1 件)
参考
カテゴリ
Help Center および File Exchange で Resizing and Reshaping Matrices についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!