Contour Plot of Rosie Function
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Hello,
I am trying to get the same plot as my professor showed in class. He said to use a for loop instead of meshgrid. I keep getting an error that X must not be a scalar. I'm not sure where I'm going wrong. Below is the plot I'm supposed to get followed by my code that is not working.
i=1; j=1;
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
clf;figure(1)
contour(a,b,f)
3 件のコメント
Adam Danz
2021 年 1 月 24 日
I'm sure it's based on some dataset, function, or algorithm that our prof must have provided at some point.
回答 (1 件)
Star Strider
2021 年 1 月 24 日
Transpose ‘f’, since ‘x1’ and ‘x2’ appear to be the same (otherwise it would also be necessary to reverse their orders in the argument list for the contour call):
i=1; j=1;
% conts=[-1 -.5 0 .5 2 3 3.5 3.6 3.7 3.8 3.9 3.98 4 4.02 4.1 4.2 4.5 5 10 ];
conts = 10.^(-1:1:3);
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
% clf;
figure(1)
contour(x1,x2,f.',conts, 'ShowText','on', 'LineWidth',1.5)
axis('equal')
.
0 件のコメント
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