How to create matrix with other matrixes by joining them?
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Hi!
I'm trying to construct a matrix from the elements of several vectors, by joining them, For example:
a = [1 2 3];
b = [4 5 6];
c = [7 8 9];
d = [10 11 12];
And it should result in:
res =
1 4 2 5 3 6
7 10 8 11 9 12
Which is:
res =
a(1) b(1) a(2) b(2) a(3) b(3)
c(1) d(1) c(2) d(2) c(3) d(3)
I would need a method that can do this for any number of vectors with the same length.
Using a for loop and clever indexing would propably be one way, but I'm looking for a solution without using loops.
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Stephen23
2021 年 1 月 11 日
a = [1 2 3];
b = [4 5 6];
c = [7 8 9];
d = [10 11 12];
res = reshape([a;c;b;d],2,[])
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Stephen23
2021 年 1 月 11 日
編集済み: Stephen23
2021 年 1 月 11 日
"There is no rule for the number of input veectors"
The product of the arrangement vector exactly specifies how many vectors you would have to have.
In the general case rather than having lots of vectors stored as separate variables (which would be very bad data design) it would be much better to store them in one numeric matrix or one cell array. An example with a cell array:
C = num2cell(reshape(1:12*3,3,12).',2); % {[1,2,3],[4,5,6],...,[34,35,36]}
A = [3,4]; % arrangement
D = reshape(C,A(2),A(1)).';
M = reshape(vertcat(D{:}),A(1),[])
If the data were stored in one numeric matrix then you could just use permute and reshape.
その他の回答 (1 件)
Mathieu NOE
2021 年 1 月 11 日
hello
here you are
no loops
res = zeros(2,2*size(a,2));
res(1,1:2:2*size(a,2)) = a;
res(1,2:2:2*size(a,2)) = b;
res(2,1:2:2*size(a,2)) = c;
res(2,2:2:2*size(a,2)) = d;
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