problem with fzero func
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I Have problem with this part of code it returns the following error 'Function values at interval endpoints must be finite and real.' in the linen where M(m)=fzero(func,x_int).I have the latest version of matlab
%% Pressione in uscita
if (11000>ALT) && (ALT<25000)
T = -56.46; %C
p_o = 1000*(22.65*exp(1.73-0.000157*ALT));
elseif ALT>=25000
T = -131.21 + 0.00299*ALT ;
p_o = 1000*(2.488*((T+273.1)/216.6)^-11.388);
else
T = 15.04 - 0.00649*ALT;
p_o = 1000*(101.29*((T+273.1)/288.08)^5.256);
end
%% Inizio il calcolo
PR = p_o/p_1;
PR2 = (p_o/p_1)^((g-1)/g);
TT = (2*g*R*T_1)/(g-1);
p_t = ((2/(g+1))^(g/(g-1)))*2.068;
v_t = sqrt((2*g*R*T_1)/(g+1));
v_e = sqrt(TT*(1-PR2));
if m_dot==0
m_dot=FT/v_e;
elseif FT==0
FT = m_dot/v_e;
else
fprintf('You can either set desired thrust OR mass flow rate')
end
T_e = T_1*(p_o/p_1)^((g-1)/g);
a_e = sqrt(g*R*T_e);
Me = v_e/a_e;
% Metodi delle caratteristiche
TR = 35; %raggio della gola in cm
RTOD = 180/pi;
DTOR = pi/180;
P = []; %punti sull' asse delle x
%% Parametrizzazione funzione di Prantl meyer
A = sqrt((g+1)/(g-1));
B = (g-1)/(g+1);
v_PM = @(x) A*atan(sqrt(B*(x^2-1))) - atan(sqrt(x^2-1));
%% Calcolo T_max, BREAK UP INTO DIVISIONS
T_max = 0.5*v_PM(Me)*RTOD;
DT = (90-T_max) - fix(90-T_max);
T(1) = DT*DTOR;
n = T_max*2;
for m = 2:T_max*2
T(m) = (DT + (m-1))*DTOR;
%Mach from T(i) using T(i) = v_PM (FALSE POSITION)
x_int = [1 1.01*Me];
func = @(x) T(m) - v_PM(x);
M(m) = fzero(func,x_int);
P(m) = 0 + TR*tan(T(m)); %X-AXIS POINTS
%RRSLOPES
RR(m) = -TR/P(m);
%LR slopes
LR(m) = tan(T(m)+asin(1/M(m)));
SL(m) = -RR(m);
end
2 件のコメント
Matt J
2021 年 1 月 8 日
For which m in the loop does this occur? Also, have you checked that func(x_int(1)) and func(x_int(2)) are both finite and real, as the error message suggests?
Mathieu NOE
2021 年 1 月 8 日
hello Francesco
would be glad to help , but we miss a bunch of initialisation of data to run this code
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