unique rows of matrix
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I have to create new matrix A from a given matrix B in the following manner
B=[1 4 2;1 5 2;1 5 2;3 3 4;3 1 4;2 1 3;2 6 3]
A=[1 2;3 4;2 3]
i-e in forming A we ignore the values which 2nd column takes in and considers only column 1 and 3 create A.
unique(A,'rows') will not do the job . Do I have to create an intermediate matrix from column 1 and 3 and the apply this unique function to get the desired matrix or is there any other option available which avoids formulation of intermediate matrix
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Matt Kindig
2013 年 3 月 25 日
You can easily perform the task using:
A = unique( B(:,[1 3]), 'rows');
But of course, this forms the intermediate matrix to run the unique() function. Is there a particular reason you need to avoid this intermediate matrix running (memory issues, perhaps)?
その他の回答 (1 件)
Matt J
2013 年 3 月 25 日
編集済み: Matt J
2013 年 3 月 25 日
You have to create an intermediate matrix, but you don't have to assign it to a variable.
A = unique(B(:,[1 3]),'rows')
What issue do you have with the above? Your B matrix is too small for this to matter and super-large matrices will be painful for UNIQUE anyway.
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