if statement find criteria not doing what I want it to do
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if k does not contain 1 matlab returns ' 1×0 empty double row vector ' so i dont understand why this is not working in my if statement, where I have wrote ' 1×0 empty double row vector' as 'zeros(1,0)'
if k does contain 1 it returns scalar 1
function[out]=neqchek(k)
c=find(k==1)
if c~=zeros(1,0)
k(1)=10
out=k
end
end
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採用された回答
David Hill
2020 年 11 月 25 日
function[out]=neqchek(k)
c=find(k==1)
if ~isempty(c)
k(1)=10
out=k
end
end
2 件のコメント
the cyclist
2020 年 11 月 25 日
編集済み: the cyclist
2020 年 11 月 25 日
The reason your code doesn't work is that checking "equality" between two empty arrays does not return a simple true value. This is why your if statement doesn't behave as you expect.
Try something as simple as
[] == []
to see what I mean.
その他の回答 (1 件)
madhan ravi
2020 年 11 月 25 日
neqchek = @(k) subsasgn(k, substruct('()', {k(1) == 1}), 10);
out = neqchek([1 : 2, 1])
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