curve of best fit from a few points

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Tom
Tom 2013 年 3 月 6 日
コメント済み: Ghada Bakaraki 2021 年 1 月 3 日
I have these points: -
x=[1 1.5 2 2.5 3];
y=[19.74 14.26 12.34 11.45 10.97];
and I know I can do a very rough approximation of a curve of best fit simply by "joining the dots" using: -
plot(x,y)
but is there a way to get MATLAB to join them using a curve of best fit?
I'm not sure exactly how to define 'curve of best fit', but I suppose an example might be if one had a string of x-values (+ & -) and each one had a corresponding y-value that was just x^2, then a curve of best fit for those points would show the get close to showing the curve y=x^2.
I obviously don't know the equation of my curve, which I guess is one of the issues that requires a certain method to be adopted over another.
  3 件のコメント
Tom
Tom 2013 年 3 月 6 日
Well I suppose some assumptions need to be made, i.e. guessing at the nature of the curve. My curve looks like it might be a hyperbola (it's similar to a positive section of y=1/x). If I assumed that then how would I proceed from there?
amberly hadden
amberly hadden 2014 年 6 月 16 日
I would suggest you in put your data in terms of x and y. next type cftool. you will get a new window which will ask you to input x and y. then creat data and next step go to fitting option and click new fitting you will see lots of curves. Fit them one by one and see which one is best fit for your data.You will get equation as well.

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採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 3 月 6 日
編集済み: Azzi Abdelmalek 2013 年 3 月 6 日
x=[1 1.5 2 2.5 3];
y=[19.74 14.26 12.34 11.45 10.97];
xi=1:0.2:3
method='spline'
yi=interp1(x,y,xi,method)
plot(xi,yi)
  3 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2013 年 3 月 6 日
If you have a curve fiting toolbox, you can use fit function
Ghada Bakaraki
Ghada Bakaraki 2021 年 1 月 3 日
this method can be used with any set of points?or only with the given set of points in the question?

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その他の回答 (3 件)

Daniel Shub
Daniel Shub 2013 年 3 月 6 日
The title of your question says line, bu the body of the question says curve. If you really interested in a straight line, then lsline will do the job.
x=[1 1.5 2 2.5 3];
y=[19.74 14.26 12.34 11.45 10.97];
plot(x,y, '*')
lsline
The source of lsline is available:
type lsline
and you can see it does all the work with polyfit, so it should be possible to create a enhanced version that fits higher order polynomials or your own custom curve.
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Daniel Shub
Daniel Shub 2013 年 3 月 6 日
Please edit the question to explain how you are defining the curve of best fit.
Tom
Tom 2013 年 3 月 6 日
Okay - done that.

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Shashank Rayaprolu
Shashank Rayaprolu 2017 年 10 月 21 日
I took the points and formed a curve using spline function (using spline method and interpl command). But now I want to get the equation of the curve generated.
How should I go about that???

Alex Sha
Alex Sha 2019 年 10 月 20 日
The equation below is good enough:
y = p1+p2/(p3-x)^2;
Root of Mean Square Error (RMSE): 0.000924797017843405
Sum of Squared Residual: 4.27624762106028E-6
Correlation Coef. (R): 0.999999958196234
R-Square: 0.999999916392469
Adjusted R-Square: 0.999999832784938
Determination Coef. (DC): 0.999999916392469
Chi-Square: 1.87530479087576E-7
F-Statistic: 11960644.0637016
Parameter Best Estimate
---------- -------------
p1 9.87104884862438
p2 9.88400654611518
p3 -0.000758647151949232
f1.jpg
  1 件のコメント
JoaquinB
JoaquinB 2019 年 11 月 15 日
How did you do that? Curve Fitting Toolbox?

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