Calling a function with no arguments
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Hi All,
In my program , I'm trying to call a function with some input arguments but no outputs as I'm using this function for the purpose of plotting.
How should its syntax look like?
[ ] = function_name( var1,var2,var3) // This line is giving me erorr : Assigning an output to an empty array is not supported.
Please suggest me a way to handle this error.
Thanks in advance!
1 件のコメント
Rik
2020 年 11 月 13 日
If you're using a function to plot, you can return the handles to the graphics object, just like the plot function does.
回答 (1 件)
Mario Malic
2020 年 11 月 13 日
編集済み: Mario Malic
2020 年 11 月 13 日
You can achieve it this way.
function function_name( var1,var2,var3)
However, imagine a situation where you'd like to edit something on the plot that you've made, then you'd have to find the handles of it which is not a problem if you have only one figure/axes, but for multiples, you could return a figure handle.
function hFigure = function_name( var1,var2,var3)
hFigure = figure(1); % if you're using it
plot(hFigure, x, y);
end
2 件のコメント
Stephen23
2020 年 11 月 13 日
@Mario Malic: are you sure about that function definition syntax? The syntax given in the documentation is:
function hFigure = function_name(var1,var2,var3)
Mario Malic
2020 年 11 月 13 日
編集済み: Mario Malic
2020 年 11 月 13 日
I haven't had my first coffee yet! I edited the answer, thanks Stephen.
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