How can I convert 100 X Y and Z coordinates generated randomly in the form of a 100x100x100 matrix

2 ビュー (過去 30 日間)
close all
clear all
n = 100;
xm = 100;
ym = 100;
zm = 100;
x = 0;
y = 0;
z = 0;
for i=1:1:n
S(i).xd=rand(1,1)*xm;
XR(i)=S(i).xd;
S(i).yd=rand(1,1)*ym;
YR(i)=S(i).yd;
S(i).zd=rand(1,1)*zm;
ZR(i)=S(i).zd;
end
this gives me 100 random x, y and z-axis. I can plot the points but how can i group them as a 3D matrix of 100x100x100 such that matrix entries are (XR(i), YR(i), ZR(i))
  4 件のコメント
Tamoor Shafique
Tamoor Shafique 2020 年 10 月 30 日
  1. XR(i), YR(i), and ZR(i) are 100 random coordinates each. for 100 iterations of i. so each iteration gives a 3d point.
  2. yes the 100 points should on the 100 should be 1 that would do.
Matt J
Matt J 2020 年 10 月 30 日
yes the 100 points should on the 100 should be 1 that would do.
But that is what I gave you below.

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採用された回答

Matt J
Matt J 2020 年 10 月 30 日
If you mean you want a 100x100x100 binary array A with one hundred randomly located entries where A(i,jk)=1, then
A=false(100,100,100);
A( randperm(numel(A),100) )=1;
whos A
Name Size Bytes Class Attributes A 100x100x100 1000000 logical
nnz(A)
ans = 100
  2 件のコメント
Tamoor Shafique
Tamoor Shafique 2020 年 10 月 30 日
I need 100x100x100 array of actual coordinates please for example (24,58,19) if thats possible. I know this might feel strange but this is the case
Tamoor Shafique
Tamoor Shafique 2020 年 10 月 30 日
so instead of ones at the corresponding location i wish to display the actual value of point

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