How to code my own Reshape function without using the built in reshape()??

Im essentially trying to make a function ---> function [matrix] = myReshape(vector, m, n) that takes in a 1d vector and dimensions m and n, and makes it a 2d matrix as shown above with the m and n provided.

How can I go about this?

[James Tursa]

Since MATLAB stores values in column order, note that your proposed "reshape" reorders the values in memory. I.e., it does not do the same thing as the MATLAB reshape( ) function. You have the equivalent of a transpose mixed in with this operation.

[Coleman tyson]

I see. Though transpose wouldn't necessarily work for me because if I want to end up with an uneven matrix of dimensions 3x4, I couldn't reshape and then transpose the reshaped matrix, because it would result in a 4x3 matrix ://

Answer 1

[Matt J]

Hint: Notice the effect of doing things like this:

A=nan(3,4);
A(:)=1:12

A = 3×4

1 4 7 10 2 5 8 11 3 6 9 12

●

[Coleman tyson]

Yeah that makes sense, but it gives the order of the values in the wrong orientation. If you look at the og question, I don't really want it to order downwards but rather horizontally. Does that make sense??

[Matt J]

Yep, you will have to figure out how to interchange rows and columns in some way.

[Coleman tyson]

hmm Ok. Thanks for the tips.

[Coleman tyson]

Wait so do you think I could do this, then transpose this array, then since the dimensions are also flipped, I could turn it into a 1d vector again, and then do this reshape thing again and then It would be ordered correctly? or is there a mistake with my logic here?

[Matt J]

Way more complicated than you need.

[Coleman tyson]

lol ok sorry D: so do you recommend using transpose at all??

[Matt J]

I recommend that you work backwards from the solution. What if you took the result that you are trying to get, and transposed that? What would that look like?